Which linear inequality is represented by the graph?

This hanger is in balance. There are two labels weight. What is the weight of each circle on grams?

Citrus2011 [14]

Answer:

since there is no image attached I can't see what weight they could be labeled but since the scale is even the weights must be the same number weight

Step-by-step explanation:

hope this helped!

6 0

2 years ago

Becky put $100 into in the account to use for school expenses. The account earns 11% interest, compounded annually. How much wil

Mnenie [13.5K]

Answer: $187 will be in the account after 6 years.

Step-by-step explanation:

We would apply the formula for determining compound interest which is expressed as

A = P(1+r/n)^nt

Where

A = total amount in the account at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount deposited

From the information given,

P = $100

r = 11% = 11/100 = 0.11

n = 1 because it was compounded once in a year.

t = 6 years

Therefore,.

A = 100(1 + 0.11/1)^1 × 6

A = 100(1 + 0.11)^6

A = 100(1.11)^6

A = $187

5 0

3 years ago

Factorize 10x3y2+5x3y3-15x4y5

d1i1m1o1n [39]

Answer:

−5x^3y^2(3xy^3−y−2)

i hope this helped :D

7 0

2 years ago

Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%. Find

Papessa [141]

Answer:

1) $\text{P(at least one boy and one girl)}=\frac{3}{4}$

2) $\text{P(at least one boy and one girl)}=\frac{3}{8}$

3) $\text{P(at least two girls)}=\frac{1}{2}$

Step-by-step explanation:

Given : Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%.

To Find : The probability of each event.

1) P(at least one boy and one girl)

2) P(two boys and one girl)

3) P(at least two girls)

Solution :

Let's represent a boy with B and a girl with G

Mr. and Mrs. Romero are expecting triplets.

The possibility of having triplet is

BBB, BBG, BGB, BGG, GBB, GBG, GGB, GGG

Total outcome = 8

$\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}$

1) P(at least one boy and one girl)

Favorable outcome = BBG, BGB, BGG, GBB, GBG, GGB=6

$\text{P(at least one boy and one girl)}=\frac{6}{8}$

$\text{P(at least one boy and one girl)}=\frac{3}{4}$

2) P(at least one boy and one girl)

Favorable outcome = BBG, BGB, GBB=3

$\text{P(at least one boy and one girl)}=\frac{3}{8}$

3) P(at least two girls)

Favorable outcome = BGG, GBG, GGB, GGG=4

$\text{P(at least two girls)}=\frac{4}{8}$

$\text{P(at least two girls)}=\frac{1}{2}$

4 0

3 years ago

Read 2 more answers

The figure below is a net for a rectangular prism. Side a = 21 inches, side b = 17 inches, and side c = 11 inches. What is the s

Nataly [62]

Answer:

The answer is 1,550

Step-by-step explanation:

First you find the area of the rectangle 1

Area = ab

=(21 in) (17in)

=357 sq in.

this will be the same for rectangle 3 = 357 sq. in.

next find the area of rectangle 2

area=ac

=(21 in) (11 in)

=231 sq in.

this will be the same for rectangle 4 = 231 sq. in.

next find the area of rectangle 5

area = bc

=(17 in) (11 in.)

=187 sq. in

this will be the same for rectangle 6 = 187 sq. in.

Next add all areas together

Total surface area = 2(ac) + 2(ab) + 2(bc)

= 2(231) sq in. + 2(357) sq in. + 2(187) sq. in

= 462 + 174+ 374

= 1550 sq. in

7 0

2 years ago