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2 years ago

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An online bookstore sells all paperback books for x dollars each. Aidan bought 7 paperback books and spent $3.95 on shipping. Ni

na bought 11 paperback books and spent $5.25 on shipping.What expression represents the total amount that Aidan and Nina spent?

1 answer:

rusak2 [61]2 years ago

8 0

Answer:

Here's the answer

Step-by-step explanation

y= 18x+9.20

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Hello, Here is a link to the answer. I am posting this link because it is a Brainly link and a verified answer brainly.com/question/219158

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2 years ago

Please help me solve this answer! :)

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Answer:

2,912 People

Step-by-step explanation:

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2 years ago

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ayme built a box in the shape of a rectangular prism with the dimensions shown. What is the volume of the box, in cubic inches?

Snezhnost [94]

Answer:

$64(in)^{3}$

Step-by-step explanation:

The volume of a box is equal to the length l times the width w times the height h.

$(lenght) \times (width) \times (height)$

Substitute the values of the length l=8, the width w=2, and the height h=4 into the formula.

$8 \times 2 \times 4$

Multiply 8 by 2.

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$64 {in}^{3}$

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Reading proficiency: An educator wants to construct a 99.5% confidence interval for the proportion of elementary school children

Shkiper50 [21]

Answer:

A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error of the interval is given by:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

In this problem, we have that:

$p = 0.69$

99.5% confidence level

So $\alpha = 0.005$ , z is the value of Z that has a pvalue of $1 - \frac{0.005}{2} = 0.9975$ , so $Z = 2.81$ .

Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.07?

This is n when M = 0.07. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.07 = 2.81\sqrt{\frac{0.69*0.31}{n}}$

$0.07\sqrt{n} = 1.2996$

$\sqrt{n} = \frac{1.2996}{0.07}$

$\sqrt{n} = 18.5658$

$(\sqrt{n})^{2} = (18.5658)^{2}$

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A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

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2 years ago

1+1=?..............................................................

KengaRu [80]

The answer is 2
1 + 1 = 2

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