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AfilCa [17]
3 years ago
5

Which rational graph has a minimum near x=-2 and a horizontal asymptote at y=1?

Mathematics
1 answer:
Arada [10]3 years ago
7 0

Answer:

Graph A.

Step-by-step explanation:

The graph has a local minimum around x=-2 since it slightly curves downwards around this region. Moreover, the graph of the rational function has a horizontal asymptote at y=1 since the graph approaches this horizontal line but never touches nor crosses it

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In a data distribution, the first quartile, the median and the means are 30.8, 48.5 and 42.0 respectively. If the coefficient sk
RUDIKE [14]

Answer:

a) The third quartile Q₃ = 56.45

b) Variance \mathbf{ \sigma^2 =2633.31}

Step-by-step explanation:

Given that :

Q_1  =  30.8

Median Q_2 =  48.5

Mean  = 42

a) The mean is less than median; thus the expression showing the coefficient of skewness is given by the formula :

SK = \dfrac{Q_3+Q_1-2Q_2}{Q_3-Q_1}

-0.38 = \dfrac{Q_3+30.8-2(48.5)}{Q_3-30.8}

-0.38Q_3  + 11.704  =  Q_3  +30.8  - 97

1.38Q_3  =  77.904

Divide both sides by 1.38

Q_3 = 56.45

b) The objective here is to determine the approximate value of the variance;

Using the relation

SK_p = \dfrac{Mean- (3*Median-2 *Mean) }{\sigma}

-0.38= \dfrac{42- (3 *48.5-2*42) }{\sigma}

-0.38= \dfrac{(-19.5) }{\sigma}

-0.38* \sigma = {(-19.5) }{}

\sigma =\dfrac {(-19.5) }{-0.38 }

\sigma =51.32

Variance =  \sigma^2 =51.32^2

\mathbf{ \sigma^2 =2633.31}

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Step-by-step explanation:

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