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yuradex [85]
3 years ago
6

Help with this geometry problem pls

Mathematics
1 answer:
anyanavicka [17]3 years ago
8 0

I believe the answer is 10. The triangle looks like it's isosceles, which would make PT and PC the same length.

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timama [110]
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5 0
3 years ago
Are triangles PRU and STQ congruent? Question 2 options:
denis23 [38]

PRU and STQ are not congruent because they aren’t the same size.

No, because they aren’t the same size.

<u>Step-by-step explanation:</u>

Both PRU and STQ triangles aren't in the same size, So it is not congruent. Triangles are congruent if two pairs of corresponding angles and a couple of inverse sides are equivalent in the two triangles.

If there are two sets of corresponding angles and a couple of comparing inverse sides that are not equal in measure, at that point the triangles are not congruent.

3 0
3 years ago
The diagram below shows a triangle.
Oliga [24]

Answer:

x times 2x divide by 2 or 2xsquared/2

Step-by-step explanation:

hope this helps!

3 0
3 years ago
Point C is the Image of C (-4,-2) under a Reflection across the x-axis.
Svetradugi [14.3K]

Step-by-step explanation:

\text {Reflection Rule for across the X-axis: } (x,y) \rightarrow (x,-y)

Using the point C (-4,-2) and the refection rule:

(-4,-2) \rightarrow(-4, 2)

\text {C' should be (-4,2)}

8 0
3 years ago
This 2 pls i need help with explanation sum
Nataliya [291]

9514 1404 393

Explanation:

<h3>8.</h3>

An exterior angle is equal to the sum of the remote interior angles. Define ∠PQR = 2q, and ∠QPR = 2p. The purpose of this is to let us use a single character to represent the angle, instead of 4 characters.

The above relation tells us ...

  ∠PRS = ∠PQR +∠QPR = 2q +2p

Then ...

  ∠TRS = (1/2)∠PRS = (1/2)(2q +2p) = q +p

and

  ∠TRS = ∠TQR +∠QTR . . . . . exterior is sum of remote interior

  q +p = (1/2)(2q) +∠QTR . . . . substitute for ∠TRS and ∠TQR

  p = ∠QTR = 1/2(∠QPR) . . . . . subtract q

__

<h3>9.</h3>

For triangle ABC, draw line DE parallel to BC through point A. Put point D on the same side of point A that point B is on the side of the median from vertex A. Then we have congruent alternate interior angles DAB and ABC, as well as EAC and ACB. The angle sum theorem tells you that ...

  ∠DAB +∠BAC +∠CAE = ∠DAE . . . . a straight angle = 180°

Substituting the congruent angles, this gives ...

  ∠ABC +∠BAC +∠ACB = 180° . . . . . the desired relation

4 0
3 years ago
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