Brainliest goes to whoever answers correctly and explains also if you want extra points answer my other questions

The angles of a triangle are 99??, 3x??, and x + 5??.

Anit [1.1K]

Since we know a triangle only has 180 degrees we can say:

99+3x+x+5=180

Then we can solve for x:

4x+104=180
4x=76

x=19

3 0

3 years ago

The marked price of a golf bag was $172.50. If sales tax was 6.5 percent, what was the total price of the bag?

Blizzard [7]

172.50 times .065=11.2125
172.50+11.2125=183.7125
The total price is $183.71

6 0

4 years ago

Read 2 more answers

Mr. Ries is looking to start a new club using his 33 statistics students. He only wishes to have 8

marishachu [46]

Answer: I do not know sorry

Step-by-step explanation:

6 0

3 years ago

What's absolute value |-8|

maks197457 [2]

The absolute value of a number can never be negative. That's because it represents the distance of a number from zero on a number line. The number $-8$ is $8$ digits to the left of zero on a number line. So, the absolute value of $-8$ would be $8$ .

Let me know if you have any questions regarding this problem!
Thanks!
-TetraFish

7 0

4 years ago

Read 2 more answers

In October 1947, the Gallup organization surveyed 1100 adult Americans and asked "Are you a total abstainer from, or do you on o

Rasek [7]

Answer:

$z=\frac{0.37-0.303}{\sqrt{0.336(1-0.336)(\frac{1}{1100}+\frac{1}{1100})}}=3.327$ .

$p_v =2*P(Z>3.327)= 0.000878$

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true proportions for this case are different so then there is enough evidence to conlcude that the real proportion change.

Step-by-step explanation:

Information provided

$X_{1}=407$ represent the number of people who answer abstainers in 1947

$X_{2}=333$ represent the number of people who answer abstainer recnetly

$n_{1}=1100$ sample 1 selected

$n_{2}=1100$ sample 2 selected

$p_{1}=\frac{407}{1100}=0.37$ represent the proportion estimated of people who answer abstainers in 1947

$p_{2}=\frac{333}{1100}=0.303$ represent the proportion estimated of people who answer abstainers recently

$\hat p$ represent the pooled estimate of p

z would represent the statistic

$p_v$ represent the p value

$\alpha=0.05$ significance level given

Hypothesis to test

We want to verify if the proportion of adult Americans who totally abstain from alcohol changed , the system of hypothesis would be:

Null hypothesis: $p_{1} = p_{2}$

Alternative hypothesis: $p_{1} \neq p_{2}$

The statistic is given by:

$z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{407+333}{1100+1100}=0.336$

Replacing the info given we got:

$z=\frac{0.37-0.303}{\sqrt{0.336(1-0.336)(\frac{1}{1100}+\frac{1}{1100})}}=3.327$

$p_v =2*P(Z>3.327)= 0.000878$

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true proportions for this case are different so then there is enough evidence to conlcude that the real proportion change.

6 0

3 years ago