D . |55|
Because 55 is smaller than 76
Hey there!
Here is your answer:
<u><em>The proper answer to this question is option "
</em></u>Reason:
<u><em>First write down the equation: </em></u>
<u><em>8
![\frac{1}{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%20)
+5
![\frac{1}{8}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B8%7D%20)
</em></u>
<u><em>Transform the mixed numbers into improper fractions.</em></u>
<u><em>8
![\frac{1}{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%20)
=
![\frac{17}{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B17%7D%7B2%7D%20)
</em></u>
<u><em>&</em></u>
<u><em>5
![\frac{1}{8}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B8%7D%20)
= </em></u><span><u><em>
![\frac{41}{8}](https://tex.z-dn.net/?f=%20%5Cfrac%7B41%7D%7B8%7D%20)
</em></u>
<u><em>Now add:</em></u>
<u><em>17×4=68</em></u>
<u><em>2×4=8</em></u>
<u><em>+</em></u>
<u><em>41×1=41</em></u>
<u><em>8</em></u></span><u><em>×1=8</em></u>
<u><em>68+41=109</em></u>
<u><em>=</em></u><span><u><em>
![\frac{109}{8}](https://tex.z-dn.net/?f=%20%5Cfrac%7B109%7D%7B8%7D%20)
</em></u>
<em>Therefore the answer would be 109/8!</em>If you need anymore help feel free to ask me!
Hope this helps!
~Nonportrit</span>
The binomial (2 · x + y)⁷ in expanded form by 128 · x⁷ + 448 · x⁶ · y + 672 · x⁵ · y² + 560 · x⁴ · y³ + 280 · x³ · y⁴ + 84 · x² · y⁵ + 14 · x · y⁶ + y⁷.
<h3>How to expand the power of a binomial</h3>
Herein we have the seventh power of a binomial, whose expanded form can be found by using the binomial theorem and Pascal's triangle. Hence, we find the following expression for the expanded form:
(2 · x + y)⁷
(2 · x)⁷ + 7 · (2 · x)⁶ · y + 21 · (2 · x)⁵ · y² + 35 · (2 · x)⁴ · y³ + 35 · (2 · x)³ · y⁴ + 21 · (2 · x)² · y⁵ + 7 · (2 · x) · y⁶ + y⁷
128 · x⁷ + 448 · x⁶ · y + 672 · x⁵ · y² + 560 · x⁴ · y³ + 280 · x³ · y⁴ + 84 · x² · y⁵ + 14 · x · y⁶ + y⁷
Then, the binomial (2 · x + y)⁷ in expanded form by 128 · x⁷ + 448 · x⁶ · y + 672 · x⁵ · y² + 560 · x⁴ · y³ + 280 · x³ · y⁴ + 84 · x² · y⁵ + 14 · x · y⁶ + y⁷.
To learn more on binomials: brainly.com/question/12249986
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