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3 years ago

A triangle has side lengths of 36 in, 27in, and 61 in. Classify it as acute, obtuse, or right.

1 answer:

7 0

When given 3 triangle sides, to determine if the triangle is acute, right or obtuse:1) Square all 3 sides.36, 27, 61 1,296, 729, 3,721 2) Sum the squares of the 2 shortest sides.1,296 + 729 = 2,025

3) Compare this sum to the square of the 3rd side.2,025 < 3,721
if sum > 3rd side² Acute Triangleif sum = 3rd side² Right Triangleif sum < 3rd side² Obtuse TriangleTherefore, it is an Obtuse TriangleSource:http://www.1728.org/triantest.htm

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Find the solution of 3 times the square root of the quantity of x plus 6 equals negative 12, and determine if it is an extraneou

Anna35 [415]

For this case we have the following equation:
$3 \sqrt{x+6}=-12$
Rewriting we have:
$\sqrt{x+6}= \frac{-12}{3}$
$\sqrt{x+6}=-4$
We raise both members of the equation to the square:
$(\sqrt{x+6})^2=(-4)^2$
Rewriting we have:
$x+6=16$
$x=16-6$
$x=10$
It's a extraneous solution because equality is not met by substituting x = 10 in the original equation:
$3 \sqrt{10+6}=-12$
$3 \sqrt{16}=-12$
$3(4)=-12$
$12=-12$
Answer:
The solution is:
$x=10$
It's a extraneous solution

6 0

3 years ago

13. The least common multiple of two non-zero integers a and b is the unique positive integer m such that (i) m is a common mult

Vlad [161]

Answer:

[a,b] divides n

Step-by-step explanation:

Let us denote the least common multiple of a and b [a,b]=m.

We want to prove that m divides n, where n is a multiple of a and b.

We suppose m does not divide n, then by the Division Theorem, there exists q and r integers such that:

(1) ... n=mq+r, where 0<r<m

As n is a multiple of a and b, there exists s and t integers such that:

sa=n and tb=n

Same thing happens to m as it is the least common multiple, there exists u and v such that:

ua=m and vb=m

So (1) has the following form:

n=mq+r ⇒ sa=uaq+r ⇒sa-uaq=r⇒(s-uq)a=r and

n=mq+r ⇒ tb=vbq+r ⇒ tb-vbq=r⇒ (t-vq)b=r

So r is a multiple of a and b, but r<m which is a contradiction as, m is the least common multiple of a and b. So this concludes the proof.

So this means that $\frac{ab}{m}$ is and integer.

As m= vb, then $\frac{m}{b}$ is an integer, lets say $\frac{m}{b}$ =v; and as m=ua, then $\frac{m}{a}$ =u.

So $\frac{ab}{m}$ v= $\frac{ab}{m}$ $\frac{m}{b}$ =a, so $\frac{ab}{m}$ divides a; on the other hand, $\frac{ab}{m}$ u= $\frac{ab}{m}$ $\frac{m}{a}$ =b, so $\frac{ab}{m}$ divides b. From this we can conclude that $\frac{ab}{m}$ is a common divisor of a and b.

4 0

3 years ago

You work at a grocery store. Last week, you sold 213 potatoes to customers and lost 6 potatoes due to expiration. The store paid

oksian1 [2.3K]

Answer:

Total Sold potatoes =213

Paid price=213*0.47=100.11

Sold price=213*0.88=187.44

Lost potatoes=2.82

=187.44-100.11-2.82

Profit =84.51

5 0

3 years ago

Plot and connect the points A (2, -2), B (-4, -4), C (-4, -1), D (-2, 3), E (1, 3), F (2, 5), and find the length of BC.

Paul [167]

Answer:

BC = 3 units

Step-by-step explanation:

Given points:

A = (2, -2)
B = (-4, -4)
C = (-4, -1)
D = (-2, 3)
E = (1, 3)
F = (2, 5)

Plot the points on the coordinate plane (x, y) and connect them in alphabetical order with straight lines (see attached).

From visual inspection of the drawn polygon, we can see that the length of BC is 3 units.

It is fairly simple to calculate the length of BC without plotting the points.

As points B and C have the same x-value, this means that the distance between them is simply the difference between their y-values.

⇒ distance = |-4 - (-1)| = |-3| = 3 units

6 0

2 years ago

Read 2 more answers

Find the value of that makes ADEFAXYZ.

vovikov84 [41]

Answer:

x = 2/3

DF = 10

scale factor of ΔDEF to ΔXYX is 1:3

Step-by-step explanation:

DF corresponds to XZ and DE corresponds to XY so we can set up a proportion:

6x+6/30 = 8/24

simplify 8/24 to be 1/3

6x+6/30 = 1/3

cross-multiply:

3(6x+6) = 30

18x + 18 = 30

18x = 12

x = 12/18 or 2/3

7 0

3 years ago