Question

Three consecutive even integers are such that the sum of the smallest and three times the second is 38 more than twice the third. Find the integers.

Answer 1

$x,\ x+2,\ x+4-\text{the three consecutive even integers}\\\\\text{The equation}\\\\x+3(x+1)=2(x+4)+38\ \ \ \ |\text{use distributive property}\\\\x+3x+3=2x+8+38\\\\3x+3=2x+46\ \ \ \ |-3\\\\3x=2x+43\ \ \ \ |-2x\\\\x=43\\x+2=45\\x+4=47$

Answer 2

Answer:

20, 22, 24

Step-by-step explanation:

since the integers are even: x, x+2, x+4

x+3(x+2)=38+2(x+4)

x+3x+6=38+2x+8

4x+6=46+2x

2x=40

x=20