The answer is 9a+5. All you have to do is combine like terms:)
Well, is namely their difference, so, let's first convert the mixed fractions to "improper", and subtract.
The length of the unknown sides of the triangles are as follows:
CD = 10√2
AC = 10√2
BC = 10
AB = 10
<h3>Triangle ACD</h3>
ΔACD is a right angle triangle. Therefore, Pythagoras theorem can be used to find the sides of the triangle.
where
c = hypotenuse side = AD = 20
a and b are the other 2 legs
lets use trigonometric ratio to find CD,
cos 45 = adjacent / hypotenuse
cos 45 = CD / 20
CD = 1 / √2 × 20
CD = 20 / √2 = 20√2 / 2 = 10√2
20² - (10√2)² = AC²
400 - 100(2) = AC²
AC² = 200
AC = √200 = 10√2
<h3>
Triangle ABC</h3>
ΔABC is a right angle triangle too. Therefore,
Using trigonometric ratio,
cos 45 = BC / 10√2
BC = 10√2 × cos 45
BC = 10√2 × 1 / √2
BC = 10√2 / √2 = 10
(10√2)² - 10² = AB²
200 - 100 = AB²
AB² = 100
AB = 10
learn more on triangles here: brainly.com/question/24304623?referrer=searchResults
Answer:
(10, - 9 )
Step-by-step explanation:
Given the 2 equations
y = - 2x + 11 → (1)
y = - 3x + 21 → (2)
Substitute y = - 2x + 11 into (2)
- 2x + 11 = - 3x + 21 ( add 3x to both sides )
x + 11 = 21 ( subtract 11 from both sides )
x = 10
Substitute x = 10 into either of the 2 equations and evaluate fir y
Substituting into (1)
y = - 2(10) + 11 = - 20 + 11 = - 9
solution is (10, - 9 )
1 2/3 + 3 1/3 = 5/1
5 5/6 - 5/1 = 5/6
5/6 was left
