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Phantasy [73]
3 years ago
5

Find the product (4x-5)(4x-1)

Mathematics
2 answers:
ipn [44]3 years ago
8 0

Answer:

80

Step-by-step explanation:

(4x-5)(4x-1) = 80

viva [34]3 years ago
5 0

Answer:

16x² - 24x + 5

Step-by-step explanation:

Given

(4x - 5)(4x - 1)

Each term in the second factor is multiplied by each term in the first factor, that is

4x(4x - 1) - 5(4x - 1) ← distribute both parenthesis

= 16x² - 4x - 20x + 5 ← collect like terms

= 16x² - 24x + 5

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Charlotte is on spring break in Mexico. She purchases a souvenir for 153 pesos, which she charges to her credit card. If the exc
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1.) multiply the US dollars by the exchange rate $213 x 80.76 = 17,201.88

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So the answer is

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6 0
4 years ago
What is the decimal to 5 Points out of 100 points
Nikolay [14]
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hodyreva [135]

Answer:

The correct answer is third option

1/√3

Step-by-step explanation:

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<u>Points to remember</u>

Tan θ = Opposite side/Adjacent side

<u>To find the value of tan(B)</u>

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Therefore the value of tan(B) =  1/√3

7 0
4 years ago
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A typical tip in a restaurant is 18% of the bill. If the bill is 150,what would the typical tip be​
Natasha_Volkova [10]

<u><em>You want to leave a 18% tip on a meal that cost $150.</em></u>

<u><em>First, convert the 18% to an actual number that can be used in a calculation. For percents,this is always done by simply dividing the percent (in this case 18%) by 100%.So, the conversational term "18%" becomes 18% / 100% = 0.18 in terms of a real mathematical number.</em></u>

<u><em>Second, you need to find out what 18% of your $150 meal cost is.This is always done by multiplying 0.18 by $150.00, or</em></u>

<u><em></em></u>

<u><em>0.18 x $150.00=$27.00.</em></u>

<u><em>So, the amount of tip you are going to leave is $27.00.</em></u>

<u><em></em></u>

<u><em>This makes the total cost of your meal (to write on your charge slip or other payment)</em></u>

<u><em></em></u>

<u><em>$150.00 + $27.00 = $177.00. </em></u>

<u><em>-By TheRealMarinette</em></u>

<u>Please do not copy N Paste This Answer.</u>

8 0
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4vir4ik [10]
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