All categories

3 years ago

Find the sum of -3x square- 4x +3 and 2x square -x +3

Mathematics

1 answer:

Lady_Fox [76]3 years ago

4 0

Answer:

−x²−4x+3−x+3

Subtract x from −4x.

−x²−5x+6

Step-by-step explanation:

You might be interested in

What sums are equal to 6/12?

nadya68 [22]

Hey there!

"What sums are equal to $\bold{\frac{6}{12}}$ ?"

$\bold{\frac{6}{12}=\frac{1}{2}=0.5 }$

It can't be $\bold{A. \frac{6}{12} + \frac{6}{12}+ \frac{6}{12}+\frac{6}{12}+\frac{6}{12}+\frac{6}{12}}$ because the answer would be $\bold{3}$
It can be $\bold{B.\frac{2}{12} + \frac{1}{12} + \frac{1}{12} +\frac{2}{12}}$
It can also be $\bold{C. \frac{5}{12} + \frac{1}{12}}$
It can also again be $\bold{\frac{1}{12}+\frac{1}{12}+\frac{1}{12}+\frac{3}{12}}$
$\boxed{\boxed{\bold{Answers: B,C,D}}}}$

Good luck on your assignment and enjoy your day!

~ $\bold{LoveYourselfFirst:)}$

6 0

3 years ago

Read 2 more answers

At the beginning of the month a store had a balance of −$554. During the month the store lost another $600. What is the current

musickatia [10]

When subtracting a number from a negative number the number appears to get larger, but in fact only becomes smaller. - 554 - 600 = - $1154

4 0

3 years ago

Read 2 more answers

Graph ∆KLM with vertices K(2,2), L(0,- 1), and M(-3,2). Graph ∆K'L'M' with a scale factor of 2. What are the coordinates of the

olasank [31]

Answer:

The coordinates of the new vertices are:

K'(4,4), L'(0,- 2), and M'(-6,4).

Step-by-step explanation:

In order to dilate a shape by 2, you can simply multiply the coordinates of the orignal triangle each by 2 to find the new coordinates of the new vertices.

K(2,2), L(0,- 1), and M(-3,2)

K'(2*2,2*2), L'(0*2,- 1*2), and M'(-3*2,2*2).

Now become...

K'(4,4), L'(0,- 2), and M'(-6,4).

You can now graph ∆K'L'M' using these coordinates.

5 0

2 years ago

A DEF has vertices D(-5,-1), E (3, 3), and F (1,-5). Find the equation of the altitude through F in

Tems11 [23]

Answer:

y = -2x -3

Step-by-step explanation:

- the altitude trough F is a perpendicular line to the line DE

- find slope of line DE

D ( x2 = -5, y2 = -1); E (x1 = 3, y1 = 3)

slope m = (y2-y1) / (x2-x1) = (-1-3) / (-5-3) = -4/ -8 = 1/2

-find equation of the altitude trough F

lines that are perpendicular have the slope negative reciprocal (negative reciprocal of 1/2 is -2)

y= -2x +b , for point F(1, -5)

-5 = -2*1 +b, add 2 to both sides

-5 +2 = b, combine like terms

-3 =b

equation of the altitude trough F is y = -2x -3

4 0

3 years ago

HELP ME!! plz? Combing like terms.

Bad White [126]

T: 8x+19

7x-2(4-2x)+6(5-x)-x+2-(6x+5) = 7x-8+2x+30+6x-x+2-6x-5 = 8x+19

Y: 56-8x

9-(-2-3x)+4(-x+6)-x+12-3(2x-3) = 9+2+3x-4x+24-x+12-6x+9 = 56-8x

5 0

3 years ago

Find the sum of -3x square- 4x +3 and 2x square -x +3​

Find the sum of -3x square- 4x +3 and 2x square -x +3