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Natali5045456 [20]
3 years ago
10

Find the sum of -3x square- 4x +3 and 2x square -x +3​

Mathematics
1 answer:
Lady_Fox [76]3 years ago
4 0

Answer:

−x²−4x+3−x+3

Subtract x from −4x.

−x²−5x+6

Step-by-step explanation:

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What sums are equal to 6/12?
nadya68 [22]

Hey there!

"What sums are equal to \bold{\frac{6}{12}}?"

\bold{\frac{6}{12}=\frac{1}{2}=0.5 }

  • It <em><u>can't</u></em> be \bold{A. \frac{6}{12} + \frac{6}{12}+ \frac{6}{12}+\frac{6}{12}+\frac{6}{12}+\frac{6}{12}}   because the answer would be \bold{3}
  • It <u><em>can </em></u> be \bold{B.\frac{2}{12} + \frac{1}{12} + \frac{1}{12} +\frac{2}{12}}
  • It <u><em>can</em></u> also be \bold{C. \frac{5}{12} + \frac{1}{12}}
  • It <em>can</em> also again be \bold{\frac{1}{12}+\frac{1}{12}+\frac{1}{12}+\frac{3}{12}}
  • \boxed{\boxed{\bold{Answers: B,C,D}}}}

Good luck on your assignment and enjoy your day!

~\bold{LoveYourselfFirst:)}



6 0
3 years ago
Read 2 more answers
At the beginning of the month a store had a balance of −$554. During the month the store lost another $600. What is the current
musickatia [10]
 When subtracting a number from a negative number the number appears to get larger, but in fact only becomes smaller. - 554 - 600 = - $1154
4 0
3 years ago
Read 2 more answers
Graph ∆KLM with vertices K(2,2), L(0,- 1), and M(-3,2). Graph ∆K'L'M' with a scale factor of 2. What are the coordinates of the
olasank [31]

Answer:

The coordinates of the new vertices are:

K'(4,4), L'(0,- 2), and M'(-6,4).

Step-by-step explanation:

In order to dilate a shape by 2, you can simply multiply the coordinates of the orignal triangle each by 2 to find the new coordinates of the new vertices.

K(2,2), L(0,- 1), and M(-3,2)

K'(2*2,2*2), L'(0*2,- 1*2), and M'(-3*2,2*2).

Now become...

K'(4,4), L'(0,- 2), and M'(-6,4).

You can now graph ∆K'L'M' using these coordinates.

5 0
2 years ago
A DEF has vertices D(-5,-1), E (3, 3), and F (1,-5). Find the equation of the altitude through F in
Tems11 [23]

Answer:

y = -2x -3

Step-by-step explanation:

- the altitude trough F is a perpendicular line to the line DE

- find slope of line DE

D ( x2 = -5, y2 = -1); E (x1 = 3, y1 = 3)

slope m = (y2-y1) / (x2-x1) = (-1-3) / (-5-3) = -4/ -8 = 1/2

-find equation of the altitude trough F

lines that are perpendicular have the slope negative reciprocal (negative reciprocal of 1/2 is -2)

y= -2x +b , for point F(1, -5)

-5 = -2*1 +b, add 2 to both sides

-5 +2 = b, combine like terms

-3 =b

equation of the altitude trough F is y = -2x -3

4 0
3 years ago
HELP ME!! plz? Combing like terms.
Bad White [126]

T: 8x+19

7x-2(4-2x)+6(5-x)-x+2-(6x+5) = 7x-8+2x+30+6x-x+2-6x-5 = 8x+19

Y: 56-8x

9-(-2-3x)+4(-x+6)-x+12-3(2x-3) = 9+2+3x-4x+24-x+12-6x+9 = 56-8x

5 0
3 years ago
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