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krok68 [10]
3 years ago
8

X=15-y y=13-z z=12-x

Mathematics
1 answer:
Ksju [112]3 years ago
8 0

Answer:

x = 7; y = 8; z = 5

Step-by-step explanation:

x = 15 - y

y = 13 - z

z = 12 - x

The first equation is solved for x. Substitute x in the third equation with 15 - y from the first equation.

z = 12 - (15 - y)

z = 12 - 15 + y

z = y - 3       (Equation 1)

Now substitute y - 3 for z in the original second equation.

y = 13 - z

y = 13 - (y - 3)

y = 13 - y + 3

2y = 16

y = 8

Substitute 8 for y in Equation 1.

z = y - 3

z = 8 - 3

z = 5

Substitute 5 for z in the original third equation.

5 = 12 - x

-7 = -x

x = 7

Solution: x = 7; y = 8; z = 5

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Answer:

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Step-by-step explanation:

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3 years ago
Solve for y in terms of x
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Answer:

(a) 3 - 2x - 2x²  (b) -21

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3 0
2 years ago
A research team is testing a product that will minimize wrinkles among women. Volunteers in the age group of 40 to 45 are includ
artcher [175]

There are mistakes in the answer options attached. These are the correct ones.

a. The group that received the bottle of solution is the control group.

b. The group that received the bottle of solution that did not contain the ingredients that are meant to lessen wrinkles is the control group.

c. Both the groups are control groups.

d. Neither group is an control group.

Answer:

B. The group that received the bottle of solution that did not contain the ingredients that are meant to lessen wrinkles is the control group

Step-by-step explanation:

In an experiment of this type, the control group is the group that does not contain the treatment. So in this group The effect of the treatment unknown unlike the experimental group which gets the treatment that the researcher is trying to find it's effect.

I. Conclusion, the group that got bottles that did not contain Ingredients for wrinkles lessening is the control group.

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3 years ago
I am in need of some help :(It looks so simple yet I don't get how to do it. Can anyone help explain?(picture of question attach
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x = 14

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height = x

base 1 = 98

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Using altitude formula in geometric mean:

base 1/height = height/base 2

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\begin{gathered} \frac{98}{x}=\frac{x}{2} \\ \text{cross multiply:} \\ 2(98)\text{ = x}\times x \end{gathered}\begin{gathered} 196=x^2 \\ \text{square root both sides:} \\ \sqrt[]{196}\text{ = }\sqrt[]{x^2} \\ x\text{ = }\sqrt[]{196} \\ x\text{ = 14} \end{gathered}

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