Answer: Hello your question is incomplete below is the missing part
Which of the following statements about Hannah’s claim is supported by the interval?
A) Hannah is likely to be incorrect because the difference in the sample means was 18.6−14.4=4.218.6−14.4=4.2 hours.
B) Hannah is likely to be incorrect because 9 is not contained in the interval.
C)The probability that Hannah is correct is 0.99 because 9 is not contained in the interval.
D)The probability that Hannah is correct is 0.01 because 9 is not contained in the interval.
E)Hannah is likely to be correct because the difference in the sample means (18.6−14.4=4.2)(18.6−14.4=4.2) is contained in the interval.
Answer : Hannah is likely to be incorrect because 9 is not contained in the interval. ( B )
Step-by-step explanation:
The statement that is supported by the interval in Hannah's claim is that
Hannah is likely to be incorrect because 9 is not contained in the interval.
Answer:
1/6; 1/2; 1/12; P(T|3) = 1/2; therefore, events are independent because P(T|3) = P(T).
Step-by-step explanation:
The probability of rolling a 3 on a six-sided die is 1/6. This is because there is one 3 out of 6 possibilities.
The probability of flipping a coin on tails is 1/2. This is because there is one side "tails" out of 2 possibilities.
The probability of rolling a 3 and flipping tails is 1/6(1/2) = 1/12.
P(T|3) = P(3 and Tails)/P(3) = 1/12 / (1/6) = 1/12(6/1) = 6/12 = 1/2
Since P(T|3) = P(3), these are independent events.
Answer:
e) The number of minutes for a car to get from the intersection to the administration building
Step-by-step explanation:
Continuous Data:
Data that can take any value (an infinite number of values) within a certain range.
For example, the statistics of a group of people form continuous data, but the number of people in that group form discrete data.
Inglés
In this case, counting items such as cars, bicycles, people, are considered discrete data. They exclusively take integer values.
But time data can take continuous values.
Answer:
x=0
This can be solved by reasoning.
And confirmed by substituting 0 into the expression.
The total distance was 35 miles. Why? Well, see below:
The student ran 3 miles each day for 5 days. That can be representative of:
Day 1: 3 miles
Day 2: 3 miles
Day 3: 3 miles
Day 4: 3 miles
Day 5: 3 miles
Adding these values together, we will find that the student ran a total of 15 miles in the first five days.
As for the next set of 5 days, we can represent this by modeling like we did above:
Day 6: 4 miles
Day 7: 4 miles
Day 8: 4 miles
Day 9: 4 miles
Day 10: 4 miles
Adding the values from the second set of days, we will find that in days 6-10, the student ran a total of 20 miles.
We can add the total values together to identify the total distance the student ran during these 10 days.
15 + 20 = 35 total miles
Hence, the student ran a total of 35 miles over the course of 10 days. If you need help, let me know and I will go ally assist you.
