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3 years ago

Hi can u guys help me thanks :)

Mathematics

2 answers:

Simora [160]3 years ago

8 0

Answer:

200 cubic inches

Step-by-step explanation:

all you have to do is multiply.

wolverine [178]3 years ago

4 0

8x5(5)= 200 cubic inches

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You weld two piece's of steel together. The toral thickness is 33/64 inch. If one piece of steel is 9/32 inch thick, how thick t

Anon25 [30]

Subtract the thickness of the known piece from the total thickness.

Because they have different denominators rewrite them to have the same.

9/32 x 2 = 18/64

Now you have 33/64 - 18/64 = 15/64

The other piece is 15/64 inch thick.

4 0

3 years ago

15 points! Thanks so much!!

Georgia [21]

For this question it is the difference of two perfect squares. This means your final answer will be (2x - 5)(2x + 5). This answer is not listed so it would be none of the above.

After review, B technically works because it is the difference of two perfect squares. This allows you to take the square root of each term while ignoring the sign and then place that back in with the original sign.

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2 years ago

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What is the probability of rolling a 2 or not rolling a 2 using a regular 6-sided number cube?

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3 years ago

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What are the roots of the polynomial equation x^3-5x+5=2x^2-5? Use a graphing calculator and a system of equations. Round nonint

leonid [27]

The right answer is c. –2.24, 2, 2.24

This question needs to be solved in two ways. First, using a graphing calculator. Next, using a system of equations.

1. Using a graphing calculator.

We have the following polynomial equation:

$x^3-5x+5=2x^2-5$

By ordering this equation we have:

$x^3-2x^2-5x+10=0$

So, we can say that this equation comes from a function given by:

$f(x)=x^3-2x^2-5x+10$

Thus, by plotting this function, we have that the graph of this function is indicated in Figure 1. By zooming, we can see, in Figure 2, that the roots of the polynomial equation are the x-intercepts of $f(x)$ which are:

$x_{1}=-2.236 \\ \\ x_{2}=2 \\ \\ x_{3}=2.236$

Finally, rounding noninteger roots to the nearest hundredth we have:

$\boxed{Root_{1}=-2.24} \\ \\ \boxed{Root_{2}=2} \\ \\ \boxed{Root_{3}=2.24}$

2. Using a system of equations.

The ordered equation is:

$x^3-2x^2-5x+10=0$

By arranging to factor out we have:

$x^3-5x-2x^2+10=0$

Then, by factoring:

$x(x^2-5)-2(x^2-5)=0$

Term $(x^2-5)$ is a common factor, thus:

$(x-2)(x^2-5)=0 \\ \\ (x-2)(x-\sqrt{5})(x+\sqrt{5})=0 \\ \\ Finally: \\ \\ \boxed{Root_{1}=-\sqrt{5}=-2.24} \\ \\ \boxed{Root_{2}=2} \\ \\ \boxed{Root_{3}=\sqrt{5}=2.24}$