Answer:
Area of shaded proton =42cm²
Answer: 2 5/15 (mixed number) or 35/15 (improper fraction)
Step-by-step explanation:
For these problems, I like to make the mixed number an improper fraction, so 7 1/3 becomes 22/3 and 5 4/5 becomes 29/5. Now, because there denominators are not the same, we can find a LCM or least common multiple to make a common denominator. 15 is the least common denominator so we can turn 22/3 to 110/15 and 29/5 to 145/15. Now we can subtract the numerators. 145-110= 35. So 35/15. It is 2 5/15 as a mixed number. Hope this helps!
Answer: 
Step-by-step explanation:
Given: A cubic kilometer=
cubic centimeters
The volume of world’s oceans=
cubic kilometers of water.
⇒ The volume of world’s oceans=
cubic centimeters of water.
Volume of a bucket = 20,000 cubic centimeters of water.
The number of bucket-loads would it take to bucket out the world’s oceans
![\Rightarrow\ n=\frac{1.4\times10^{9+15}}{0.2\times10^5}......[a^n\times a^m=a^{m+n}]\\\Rightarrow\ n=7\times10^{24-5}.....[\frac{a^m}{a^n}=a^{m-n}]\\\Rightyarrow\ n=7\times10^{19}](https://tex.z-dn.net/?f=%5CRightarrow%5C%20n%3D%5Cfrac%7B1.4%5Ctimes10%5E%7B9%2B15%7D%7D%7B0.2%5Ctimes10%5E5%7D......%5Ba%5En%5Ctimes%20a%5Em%3Da%5E%7Bm%2Bn%7D%5D%5C%5C%5CRightarrow%5C%20n%3D7%5Ctimes10%5E%7B24-5%7D.....%5B%5Cfrac%7Ba%5Em%7D%7Ba%5En%7D%3Da%5E%7Bm-n%7D%5D%5C%5C%5CRightyarrow%5C%20n%3D7%5Ctimes10%5E%7B19%7D)
hence, 
bucketloads would it take to bucket out the world’s oceans.
50% is equal to the so we can easily divide 9 by 2 to get your answer 4.50 there is no hundreths for it is a clean divide (4.5×2=9)
The prime Factorization of 60 is 2,2,3,5!!
