Answer:
10) f'(x) = (x² + 6x - 3)/(x + 3)²
11) g'(x) = 1 - csc²x
Step-by-step explanation:
10. f(x) = x(1 - (4/(x + 3))
Expanding gives;
f(x) = x - (4x/(x + 3))
Differentiating gives;
f'(x) = 1 - 4/(x + 3) + 4x/(x + 3)²
Simplifying this gives;
f'(x) = [(x + 3)² - 4(x + 3) + 4x]/(x + 3)²
f'(x) = (x² + 6x + 9 - 4x - 12 + 4x)/(x + 3)²
f'(x) = (x² + 6x - 3)/(x + 3)²
11. g(x) = x + cot x
Rewriting this gives;
g(x) = x + (1/tan x)
We know that derivative of tan x is sec x while derivative of (1/tan x) is -csc²x
Thus;
g'(x) = 1 - csc²x
This can be written as
Differentiating this gives;
g'(x) = 1 - csc²x
The answer would be -9
I hope this helps.
Answer:
1/10
Step-by-step explanation:
1/2 ÷ 5
First you must use the form KCF, or Keep Change Flip
Keep the first integer (1/2)
Change the symbol (÷) > (×)
Flip the last remaining integer (5) > (1/5)
You remain with
1/2 x 1/5
Keep the numerator the same (since 1 x 1 = 1)
Multiply the denominators ( 2 x 5 = 10)
The answer is 1/10
Answer:
and 
Step-by-step explanation:
Let
x -----> the altitude of a commercial aircraft
we know that
The expression " A minimum altitude of 29,000 feet" is equal to

All real numbers greater than or equal to 29,000 ft
The expression " A maximum altitude of 41,000 feet" is equal to

All real numbers less than or equal to 41,000 ft
therefore
The compound inequality is equal to
and 
All real numbers greater than or equal to 29,000 ft and less than or equal to 41,000 ft
The solution is the interval ------> [29,000,41,000]
Answer:
a)4c +12 b)10x + -14 c) 3x+5 d)11y+(-1)
Step-by-step explanation:
as the nos without the variables can be added we can add the integers