Answer:
its the 3rd won
Step-by-step explanation:
Answer:
a. 3/4 inches per minute
b. -1 1/8 inches per minute
c. B is fastest; 1 1/8 is more than 3/4
Step-by-step explanation:
A <em>change</em> is a <em>difference</em>. A <em>rate of change</em> is <em>one difference divided by another</em>, usually the change in y-value divided by the change in x-value.
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<h3>a.</h3>
The change in elevation is the difference between the elevation at the end of the period (6 inches) and the elevation at the beginning of the period (3 inches). The change in time period is the difference between the end time (8 min) and the beginning time (4 min).
change in elevation per minute = (6 -3 inches)/(8 -4 min)
= (3 inches)/(4 min) = 3/4 inches/minute
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<h3>b.</h3>
Similarly, ...
change in elevation per minute = (3 -7 1/2 inches)/(18 -14 min)
= (-4 1/2 inches)/(4 min) = -1 1/8 inches/minute
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<h3>c.</h3>
We know that 3/4 is more than -1 1/8, but when we talk about the "fastest rate of change", we're generally interested in the magnitude--the value without the sign. That means we understand a rate of change of -1 1/8 inches per minute to be "faster" than a rate of change of 3/4 inches per minute.
The rate of change from Part B is fastest. 1 1/8 inches per minute is more than 3/4 inches per minute.
Answer:
5x+56
Step-by-step explanation:
5x+8(5+2)
5x+8(7)
Find a number that both of the denominates make the same number for example if one denominator is 1/7 and the other is 2/6 then you
2/6 * 7 = 14 over 42 then the other one would be 1/7 *6 which would be 6 over 42 you find common denominators by finding a number both of the bottom ones can equal. hope this helps
Answer:
c) t-test of population mean
Explanation:
The t-test statistic is used in hypothesis testing. Here we would use a one sample t test to test our hypothesis. The one sample t test measures the statistical difference between the hypothesized mean and the sample mean. In a one sample t test or single sample t test, a test variable is measured against a test value.
Example we compare our test variable to the hypothesized mean value $75 above.
The t test is used instead of z score when standard deviation is unknown.
Using the t test, we either accept or reject the null hypothesis given alternative hypothesis.
