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Kobotan [32]
3 years ago
6

Sabiendo que z1 = 10, z2 = 20, z3 =10 , z4 = 20, n1 = 1200 rpm.

Computers and Technology
1 answer:
romanna [79]3 years ago
7 0

Answer:

a. engranaje 1 → engranaje 2 → engranaje 3 → engranaje 4

     z1 = 10            z2 = 20              z3 =10            z4 = 20

b. n2 = 600 rpm, n3 = 1200 rpm, n4 = 600 rpm

   la relacion de transmision = 2

Explanation:

where z1 = 10, z2 = 20, z3 = 10, z4 = 20

and n1 = 1200 rpm

n2 = n1 * z1/z2 = (1200 * 10)/ 20 = 600 rpm

n3 = n2 * z2/z3 = (600 * 20)/ 10 = 1200 rpm

n4 = n3 * z3/z4 = (1200 * 10)/ 20 = 600 rpm

la relacion de transmision = z2/z1 * z3/z2 * z4/z3

= 20/10 * 10/20 * 20/10 = 2 * 0.5 * 2 = 2

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write a program that keeps names and email addresses in a dictionary as key-value pairs. the program should display a menu that
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To write a program that keeps names and email addresses in a dictionary as key-value pairs check the code given below.

<h3>What is key-value pairs?</h3>

In a key-value pair, two related data elements are combined: a value, which is a variable that belongs to the set (for example, male/female, green, 100), and a key, which is a constant that defines the data set (for example, gender, color, price).

A key-value pair could look something like this when fully formed:

gender = male

color = green

price > 100

↓↓↓//<u>Python code</u>//↓↓↓

import pickle

import sys

try:

   f=open('email.dat','rb')

   d=pickle.load(f)  

   f.close()

     

except:    

   d={}

while True:

   print('\n1. Find a email address')

   print('2. Add name and email address')

   print('3. Change an email address')

   print('4. Delete an email address')

   print('5. Exit\n')

   choice=input('\nEnter a choice: ')

   if choice:

       choice=int(choice)

   else:

       print('\nEnter a number')

       continue    

   if choice == 1:

       while True:

           name=input('\nEnter the name ')

           if name:

               if name in d:

                   print('\n%s is the email id of %s \n' % (d[name],name))

                   break

               else:

                   print('\n Email not found \n')

                   break

           else:

               print('\nName cannot be empty\n')

               continue

           

   elif choice==2:

       while True:            

       

           name=input('\nEnter the name ')

           if name:

               break;

           else:

               print('\nName cannot be empty \n')

               continue

       while True:            

       

           email=input('\nEnter the email address ')

           if email:

               d[name]=email

               break

           else:

               print('\nEmail cannot be empty\n')

               continue

           

   elif choice==3:

       while True:            

       

           name=input('\nEnter the name to change the email address ')

           if name:

               if name in d:

                   email=input('\nEnter the new email address ')

                   d[name]=email

                   print('\nEmail address changed \n')

                   break;

               else:

                   print('\nName not found \n')

                   break

           else:

               print('\nName cannot be empty \n')

               continue

           

   elif choice == 4:

       while True:            

       

           name=input('\nEnter the name to remove ')

           if name:

               if name in d:

                   del d[name]

                   print('\nName and Email address removed \n ')

                   break;

               else:

                   print('\nName not found \n')

                   break

           else:

               print('\nName cannot be empty\n')

               continue

   elif choice == 5:

       

       f=open('email.dat','wb')

       pickle.dump(d,f)

       f.close()

       sys.exit()

   else:

       print('\nEnter a valid choice ')    

Learn more about key-value pair

brainly.com/question/29414672

#SPJ1

3 0
1 year ago
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