3 years ago

Evaluate cos(θ) when θ=3π/2?

Mathematics

1 answer:

Ivanshal [37]3 years ago

3 0

Answer:

Step-by-step explanation:

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Answer: $\angle QRO=67^{\circ}$

Step-by-step explanation:

Since, If a quadrilateral is inscribed in a circle then the sum of one pair of opposite angles must be equal to 180°.

And, here quadrilateral OPQR is inscribed in circle N.

Thus, $\angle O+\angle Q=180^{\circ}$ -------(1)

And, $\angle P+\angle R=180^{\circ}$ -------(2)

According to the question, $\angle O=(x+17)^{\circ}$ , $\angle Q=(6x-5)^{\circ}$

And, $\angle R=(2x+19)^{\circ}$ -------(3)

We have to find out $\angle QRO$ or $\angle R$ .

Thus, from equation (1), $(x+17+6x-5)^{\circ}=180^{\circ}$ ⇒ $x=24^{\circ}$

Therefore, From equation (3), $\angle QRO=\angle R= (48+19)^{\circ}$

⇒ $\angle QRO=67^{\circ}$

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