Answer:
The equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x is ![\mathbf{y=-\frac{2}{3}x+3 }](https://tex.z-dn.net/?f=%5Cmathbf%7By%3D-%5Cfrac%7B2%7D%7B3%7Dx%2B3%20%7D)
Step-by-step explanation:
We need to Write the equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x
The equation in slope-intercept form is:
where m is slope and b is y-intercept.
Finding Slope:
The both equations given are parallel. So, they have same slope.
Slope of given equation y= - 2/3x is m = -2/3
This equation is in slope-intercept form, comparing with general equation
where m is slope , we get the value of m= -2/3
So, slope of required line is: m = -2/3
Finding y-intercept
Using slope m = -2/3 and point (-3,5) we can find y-intercept
![y=mx+b\\5=-\frac{2}{3}(-3)+b\\5=2+b\\ b=5-2\\b=3](https://tex.z-dn.net/?f=y%3Dmx%2Bb%5C%5C5%3D-%5Cfrac%7B2%7D%7B3%7D%28-3%29%2Bb%5C%5C5%3D2%2Bb%5C%5C%20b%3D5-2%5C%5Cb%3D3)
So, we get b = 3
Now, the equation of required line:
having slope m = -2/3 and y-intercept b =3
![y=mx+b\\y=-\frac{2}{3}x+3](https://tex.z-dn.net/?f=y%3Dmx%2Bb%5C%5Cy%3D-%5Cfrac%7B2%7D%7B3%7Dx%2B3)
The equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x is ![\mathbf{y=-\frac{2}{3}x+3 }](https://tex.z-dn.net/?f=%5Cmathbf%7By%3D-%5Cfrac%7B2%7D%7B3%7Dx%2B3%20%7D)