One: Graphs help you solve equations, and equations help you solve graphs.
<span>Because the graph is a diagram of the equation, showing at its simplest the y answer for each value of x.
Two: </span>You have to solve for y, graph it, and then find where the lines intersect.You can take a table and put in all the x and y valuesThen graph it.. And see where it intersectsBecause usually these equations are lines.<span>
</span>
Answer:
1/3 of a pear
Step-by-step explanation:
Answer:
Uranus
Step-by-step explanation:
- It is about 1,800,000,000 miles from the sun, about 36,000 miles in diameter, and it is a period of revolution around the sun is nearly 84 of our years.
Hope this helps :)
1. It's useful to divide out the GCF first because it makes factoring easier because the coefficients are smaller requiring less steps. 2. First, identify a,b, and c in the trinomial ax^2+bx+c. Then, write down all factor pairs of c Then, identify which factor pair from the previous step sums up to b. Then, Substitute factor pairs into two binomials 3. Key features are the y-intercept the zeros and the end behavior. to graph these put a pont on the intercepts and draw a line through them that matches the end behavior. 4. A binomial that is the difference of perfect squares is in the form of a^2-b^2 And its factor form is a^2 - b^2=(a-b)(a+b)5. Factoring by grouping often works well with four-term polynomials but the last step of factoring the common binomial only works when both terms contain the exact same binomial.
Should be right
Answer:
No, because the 95% confidence interval contains the hypothesized value of zero.
Step-by-step explanation:
Hello!
You have the information regarding two calcium supplements.
X₁: Calcium content of supplement 1
n₁= 12
X[bar]₁= 1000mg
S₁= 23 mg
X₂: Calcium content of supplement 2
n₂= 15
X[bar]₂= 1016mg
S₂= 24mg
It is known that X₁~N(μ₁; σ²₁), X₂~N(μ₂;δ²₂) and σ²₁=δ²₂=?
The claim is that both supplements have the same average calcium content:
H₀: μ₁ - μ₂ = 0
H₁: μ₁ - μ₂ ≠ 0
α: 0.05
The confidence level and significance level are to be complementary, so if 1 - α: 0.95 then α:0.05
since these are two independent samples from normal populations and the population variances are equal, you have to use a pooled variance t-test to construct the interval:
[(X[bar]₁-X[bar]₂) ± * ]
[(1000-1016)±2.060*23.57*]
[-34.80;2.80] mg
The 95% CI contains the value under the null hypothesis: "zero", so the decision is to not reject the null hypothesis. Then using a 5% significance level you can conclude that there is no difference between the average calcium content of supplements 1 and 2.
I hope it helps!