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AveGali [126]
3 years ago
6

Factoring polynomials

Mathematics
1 answer:
Anton [14]3 years ago
3 0
That's not a question, so idk what you need me to answer.. sorry
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Heights of young adult women in the United States are approximately Normal with a mean of 64 inches and standard deviation 2.7 i
sweet-ann [11.9K]

Answer:

The proportion of all young adult women in the United States are taller than 6 feet(72 inches ) is  

   P( X >  72) =0.0015233

Step-by-step explanation:

From the question we are told that

   The mean is  \mu =  64 \ inches

    The standard deviation is  \sigma =  2.7 \  inches

Generally  6 feet  is equivalent to 6 * 12 = 72 inches

Generally the proportion of all young adult women in the United States are taller than 6 feet(72 inches ) is mathematically represented as

       P( X >  72) =  P(\frac{X - \mu }{\sigma }  >  \frac{72  - 64 }{ 2.7 } )

\frac{X -\mu}{\sigma }  =  Z (The  \ standardized \  value\  of  \ X )

       P( X >  72) =  P(Z >  2.963 )

From the z-table

  The area under the normal  curve to the right corresponding to 2.963  is  

     P(Z >  2.963 ) = 0.0015233

=>   P( X >  72) =0.0015233

3 0
2 years ago
How are the step by step math problem suppose to be for this math problem (-2-8)^2?
Sidana [21]

Answer:

the answer is 100

Step-by-step explanation:

(-2-8)^2

(-2-8)(-2-8)

-2(-2-8)-8(-2-8)

4+16+16+64

20+80

100

6 0
2 years ago
Researchers randomly surveyed people at two amusement parks, Funland and Thrillville, to find out how many times they visit the
STALIN [3.7K]

On average, people visit Thrillville 2 more times per year than Funland.

<h3><u>Averages</u></h3>

To determine how many more times per year, on average, do people visit Thrillville than Funland, the following calculation must be performed:

  • Funland: 4,1,2,1,5,6,3,2,4,3,2,6,1,3,2 = 45
  • 45 / 15 = 3
  • Thrillville: 8,6,5,7,2,5,4,2,1,9,3,8,3,7,5,2,9,4,2,8 = 100
  • 100 / 20 = 5
  • 5 - 3 = 2

Therefore, on average, people visit Thrillville 2 more times per year than Funland.

Learn more about averages in brainly.com/question/2426692

4 0
2 years ago
A 15 ounce alloy containing 30% gold was mixed with an alloy containing 5% gold to get an alloy containing 20% gold. How many ou
Studentka2010 [4]

Answer:

4.5 % alloy

Step-by-step explanation:

Let x = amt of 30% alloy

The resulting total is to be 25 oz, therefore:

(25-x) = amt of 5% alloy:

A typical mixture equation:

.30x + .05(25-x) = .20(25)

.30x + 1.25 - .05x = 5 .30x - .05x = 5 - 1.25

.25x = 3.75

x = 3.75%2F.25

x = 15 oz of 30% alloy required

then

25-15 = 10 oz of 5% alloy:

Check solution

.30(15) + .05(10) = .20(25)

4.5 + .5 = 5

4 0
2 years ago
Whats 1-2x+3y for x=-2 and y=-5 ?​
lawyer [7]

Answer:

-10

Step-by-step explanation:

2*-2=-4

3*-5=-15

1-(-4)+(-15)=-10

5 0
2 years ago
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