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zaharov [31]
3 years ago
13

Help please answer!this is on Zearn.org

Mathematics
2 answers:
satela [25.4K]3 years ago
8 0

Answer:

3/14 this is correct answer

Step by step explanation

3 over 14

aalyn [17]3 years ago
4 0
The answer to this is 3/14
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If log (m + n) = log m+log n, show that m =n/n-1​
Sedbober [7]

log (m + n) = log m+ log n and proved it m =n/n-1​

Given;

If log (m + n) = log m+ log n

To show that the m =n/n-1​

Now, According to the question:

We know that,

Log (m + n) = log m + log n

Log (m + n ) = log (mn).                 [log a + log b = log ab ]

Cancelling the log on both sides.

then,

m + n = mn

=> n = mn - m

=> n = m (n - 1)

=> m = n / n - 1

Hence Proved

log (m + n) = log m+ log n and proved it m =n/n-1​

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A logarithm is the power to which a number must be raised in order to get some other number (see Section 3 of this Math Review for more about exponents). For example, the base ten logarithm of 100 is 2, because ten raised to the power of two is 100: log 100 = 2.

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10^-2 as a exponential notation
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Step-by-step explanation:

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