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3 years ago

13) You are setting the combination on a

Mathematics

1 answer:

Andre45 [30]3 years ago

3 0

Answer:

there are 9 possibilities I think

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How do i expand (3x+5)^2

shepuryov [24]

I don't know how you expand it but the answer is 3x + 25 unless that's expanding.

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Find three consecutive odd integers that have a sum of 9. Order them from least to greatest.

fomenos

Answer:

1, 3, 5

Step-by-step explanation:

They're odd, consecutive, and equal 9.

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3 years ago

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Can some won help me pls

exis [7]

Answer:

Just see how are they alike and differents

Step-by-step explanation:

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3 years ago

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If a cylinder with height 9 inches and radius rr is filled with water, it can fill a certain pitcher. How many of these pitchers

katrin2010 [14]

Answer:

9 pitchers

Step-by-step explanation:

Given

Cylinder 1:

$Radius = r$

$Height = 9$

Cylinder 2:

$Radius = 3r$

$Height = 9$

Required

How many pitchers' cylinder 2 can fill

First, we calculate the volume of both cylinders

Volume is calculated as:

$Volume = \pi r^2h$

For A:

$V_A = \pi r^2*9$

$V_A = 9\pi r^2$

For B:

$V_B = \pi (3r)^2 * 9$

$V_B = \pi *9r^2 * 9$

$V_B = 9* 9\pi r^2$

In (a): $V_A = 9\pi r^2$

So, we have ve:

$V_B = 9*V_A$

$V_B = 9V_A$

<em>If the first cylinder can fill 1, then the second can fill 9 pitchers</em>

7 0

3 years ago

When studying radioactive material, a nuclear engineer found that over 365 days, 1,000,000 radioactive atoms decayed to 973 co

HACTEHA [7]

Answer:

A. number of decayed atoms = 73.197

Step-by-step explanation:

In order to find the answer we need to use the radioactive decay equation:

$N(t)=N0*e^{kt}$ where:

N0=initial radioactive atoms

t=time

k=radioactive decay constant

In our case, when t=0 we have 1,000,000 atoms, so:

$1,000,000=N0*e^{k*0}$

$1,000,000=N0$

Now we need to find 'k'. Using the provied information that after 365 days we have 973,635 radioactive atoms, we have:

$973,635=1,000,000*e^{k*365}$

$ln(973,635/1,000,000)/365=k$

$-0.0000732=k$

A. atoms decayed in a day:

$N(t)=1,000,000*e^{-0.0000732t}$

$N(1)=1,000,000*e^{-0.0000732*1}$

$N(1)= 999,926.803$

Number of atoms decayed in a day = 1,000,000 - 999,926.803 = 73.197

B. Because 'k' represents the probability of decay, then the probability that on a given day 51 radioactive atoms decayed is k=0.0000732.

4 0

3 years ago