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Afina-wow [57]
3 years ago
14

Help please! ill give brainliest if it’s correct

Mathematics
1 answer:
ivanzaharov [21]3 years ago
7 0

Answer:

2

Step-by-step explanation:

I think

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You jog 623 miles around a track each day. If you jogged that distance 4
givi [52]

Answer:

6 2/3 miles times 4

Step-by-step explanation:

Convert the fraction 2/3 to a decimal

2/3  = .67

6.67 miles times 4 = 26.68 miles

or 6x4= 24

2/3+2/3+2/3+2/3  =8/3 or 2 2/3

2 2/3 +24 =26 2/3 miles

Hope this helps, have a nice day/night! :D

3 0
3 years ago
Using the set of data below, which statements are true? Check all that apply. 13, 11, 16, 12, 42, 8 The mean of this data set is
Iteru [2.4K]
8, 11, 12, 13, 16, 42

Add together and divide by 6 to get the mean.

102/6 = 17

Find the middle of the data for the median.
(12 + 13)/2 = 12.5

The mean is 17, the median is 12.5, and the mean is more affected by the outlier.  17 (the mean) is not a good measure of center.
4 0
3 years ago
Read 2 more answers
Convert 26.2 mi to kilometers using 1 mi = 1.6 km.
PilotLPTM [1.2K]
1mile=1.6 kilometer
26.2miles=26.2*1.6=41.92 kilometers
6 0
4 years ago
Read 2 more answers
I have the answer to the problem but I need the work to go along with it, would anyone want to help?​
Alex_Xolod [135]

Answer:

thank u for the point /;

Step-by-step explanation:

4 0
3 years ago
If f(x)=x-6 and g(x)=x^3, find G(f(x)) a)x^3(x-7) b)x^3-7 c)x^3+x-7 d)(x-7)^3
nirvana33 [79]

Answer:

(x-6)^3

Step-by-step explanation:

f(x)=x-6 \\\\g(x)=x^3 \\\\g(f(x))=(x-6)^3

Hope this helps!

4 0
3 years ago
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