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AnnyKZ [126]
3 years ago
10

Gerald recorded the gains and losses for each play on the football field. Gains were marked with a + and losses with a –. Play 1

2 3 4 Yards +4 –6 –2 +3
Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
4 0

Answer:

Play 3

Step-by-step explanation:

Given:

\left\begin{array}{ccccc}{Play}&{1}&{2}&{3}&{4}&{Yards}&{+4}&{-6}&{-2}&{+3}\end{array}\right

Required [Missing from the question]:

Determine the play with the least change in yard?

To do this, we ignore the sign in front of each yard before we analyze.

So, we have:

Play 1 has a change of 4

Play 2 has 6

Play 3 has 2

Play 4 has 3

<em>From the above analysis, play has the least (which is 2)</em>

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Answer:

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Step-by-step explanation:

The question is not clear. You have indicated the original function as 12sin(0) - 9sin²(0)

If so, the solution is trivial. At 0, sin(0) is 0 so the solution is 0

However, I will assume you meant the angle to be \theta rather than 0 which makes sense and proceed accordingly

We can find the maximum or minimum of any function by finding the first derivate and setting it equal to 0

The original function is

f(\theta) = 12sin(\theta) - 9 sin^2(\theta)

Taking the first derivative of this with respect to \theta and setting it equal to 0 lets us solve for the maximum (or minimum) value

The first derivative of f(\theta) w.r.t \theta is

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And setting this = 0 gives

12\cos\left(\theta\right)-18\cos\left(\theta\right)\sin\left(\theta\right) = 0

Eliminating cos(\theta) on both sides and solving for sin(\theta) gives us

sin(\theta) = \frac{12}{18} = \frac{2}{3}

Plugging this value of sin(\theta) into the original equation gives us

12(\frac{2}{3}) - 9(\frac{4}{9} ) = 8 - 4 = 4

This is the maximum value that the function can acquire. The attached graph shows this as correct

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You need to wrap a present that is in the shape of a rectangle prism. The present has a length of 5 inches, a width of 4.5 inche
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