Answer:
cost of system is $175 and cost of the games is $525
Step-by-step explanation:
Let us take the cost of the system to be X.The games cost 3 times as much as the system and are therefore given 3X. The total cost of the system and the games is $700.Therefore,we form the equation 3X+X=$700.Meaning that 4X=$700 and X is equal to $175.The cost of the system is X therefore it is $175 and the cost of the games is 3X and is therefore $525.
Answer:
A and C
Step-by-step explanation:
I had it on a test
Answer:
Step-by-step explanation:
Let r represent Linda's walking rate.
We have been given that Linda can ride 9 mph faster than she can walk, so Linda's bike riding rate would be miles per hour.
We have been given that Linda can bicycle 48 miles in the same time as it takes her to walk 12 miles.
Since both times are equal, so we will get:
Therefore, the equation can be used to solve the rates for given problem.
Cross multiply:
Therefore, Linda's walking at a rate of 3 miles per hour.
Linda's bike riding rate would be miles per hour.
Therefore, Linda's riding the bike at a rate of 12 miles per hour.
Your Answer Will Be Between 5 and 6 Because The Square Root Of 29 Is 5.3851 ect
He has enough memory space to download a song that will use 0.12 gigabytes of memory
The memory capacity of new cell phone = 1.5 gigabytes
The memory capacity that already used = 1.35 gigabytes
The remaining space = The memory capacity of new cell phone - The memory capacity that already used
Substitute the values in the equation
Here we have to use the subtraction
The remaining space = 1.5 - 1.35
Subtract the terms
= 0.15 gigabytes
The size of the song = 0.12 gigabytes
We know 0.15 > 0.12
Hence, he has enough memory space to download a song that will use 0.12 gigabytes of memory
The complete question is
Devin has a new cell phone that holds 1.5 gigabytes if memory for music. He has already used 1.35 gigabytes of the memory. Will he have enough space to download a song that will use 0.12 gigabyte of memory? Explain.
Learn more about subtraction here
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