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3 years ago

The perimeter of a rectangle is 30meter. If the length is twice the width, what is the width?

Mathematics

1 answer:

Nataly_w [17]3 years ago

3 0

Let the length of the rectangle be L and the width be W.

Given that the length is twice the width, Then :

L = 2W .....(1)

But we know that the perimeter is 36.

==> 2L + 2W = 36

==> 2L + L = 36

==> 3L = 36

==> L = 36/3 = 12

==> W = 12/2 = 6

Now we will calculate the area:

==> A = L * W = 12* 6 = 72 square feet.

Then the area of the rectangle is 72 square feet.

I am 100% sure that that would be the answer!!

have fun!!1

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I NEED HELP PLEASEEE

Gwar [14]

Answer:

b = $\sqrt{333}$

Step-by-step explanation:

1. We can use the Pythagorean Theorem to find the missing side, b.

$14^2 + b^2 = 23^2$

2. (Solving)

Step 1: Simplify both sides of the equation.

$(14*14)+b^2 =(23*23)$
$196 + b^2 = 529$

Step 2: Subtract 196 from both sides.

$196 + b^2 - 196 = 529 - 196$
$b^2 = 333$

Step 3: Take square root of both sides.

$\sqrt{b^2} = \sqrt{333}$
$b = \sqrt{333}$

Step 4: Check if solution is correct.

$14^2 + \sqrt{333^2} = 23^2$
$(14*14)+(\sqrt{333} *\sqrt{333})=23*23$
$196 + 333 = 529$
$529 = 529$

Therefore, b = $\sqrt{333}$ .

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