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guapka [62]
3 years ago
15

Solve for x It is geometry so anyone got it?

Mathematics
2 answers:
Sauron [17]3 years ago
7 0

Answer:

X=26

Step-by-step explanation:

180-105=75

26•2=52. 52+23=75°

MissTica3 years ago
4 0
26 is the answer for x
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Marcus needs 3 1/10 m of blue fabric and 1 1/5 m of yellow fabric to make his costume. How much more blue fabric than yellow fab
Kamila [148]

Answer:

1\frac{9}{10}\ m

Step-by-step explanation:

we know that

To find out how much more blue fabric than yellow fabric does Marcus need, subtract the quantity of yellow fabric from the quantity of blue fabric

step 1

Convert mixed number to an improper fraction

3\frac{1}{10}\ m=\frac{3*10+1}{10}=\frac{31}{10}\ m

1\frac{1}{5}\ m=\frac{1*5+1}{5}=\frac{6}{5}\ m

step 2

Subtract the numbers

\frac{31}{10}-\frac{6}{5}=\frac{31}{10}-\frac{12}{10}=\frac{19}{10}\ m

Convert to mixed number

\frac{19}{10}\ m=\frac{10}{10}+\frac{9}{10}=1\frac{9}{10}\ m

7 0
3 years ago
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A theater has 50 seats on the front row. There are four additional seats in each following row. PART B: How many seats would the
Roman55 [17]
132, if you add four to 50, and keep going until you get to 20
7 0
3 years ago
What is the following product square root 10* square root 10
VMariaS [17]

Answer: 10

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
PLEASE HELP ON #3 ASAP!
IrinaK [193]

9514 1404 393

Answer:

  1a: x+3 = 5

  1c: 6 = 2z

  2b: x = 2

  2d: 3 = z

  3: the solutions make the hangars balance

Step-by-step explanation:

1. We can write the equations by listing the contents of the hangar and using an equal sign to show the balance between left side and right side. It can work well to put left side contents of the hangar on the left side of the equal sign.

  A: x + 3 = 5

  C: 1 + 1 + 1 + 1 + 1 + 1 = z + z  simplifies to  6 = 2z

__

2. B: We can subtract 3 from both sides of the hangar (and equation) to find the value of x.

  (x +3) -3 = 5 -3

  x = 2 . . . . . hangar balances with 2 on the right

D: We can divide both sides of the hangar by 2, splitting the content into two equal parts. Then one of those parts can be removed from each side.

  2(3) = 2(z)

  3 = z . . . . . . hangar balances with 3 on the left

__

3. The found values will keep the hangar in balance when they are substituted for the corresponding variables.

  A: 2 + 3 = 5

  C: 1 + 1 + 1 + 1 + 1 + 1 = 3 + 3

4 0
3 years ago
A system of equations is shown below: n = 3m + 5 n − 2m = 3 What is the solution, in the form (m, n), to the system of equations
marshall27 [118]
n=3m+5 \\
n-2m=3 \\ \\
\hbox{substitute 3m+5 for n in the second equation:} \\
3m+5-2m=3 \\
m+5=3 \\
m=3-5 \\
m=-2 \\ \\
n=3m+5 \\
n=3 \times (-2)+5 \\
n=-6+5 \\
n=-1 \\ \\
(m,n)=(-2,-1)

The answer is C.
4 0
3 years ago
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