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pshichka [43]
3 years ago
10

5x−6=3x−6+2x has one solution many solution no solution

Mathematics
1 answer:
Tom [10]3 years ago
8 0

Answer:

infinite solutions

Step-by-step explanation:

Combine like terms:

5x - 6 = 3x - 6 + 2x

5x = 3x - 6 + 6 + 2x

5x = 3x + 2x

5x = 5x

----    ----

5      5

------------

x = x

Because this is true and any number x will make the equation true, there will be infinite solutions.

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Suppose that surface σ is parameterized by r(u,v)=⟨ucos(3v),usin(3v),v⟩, 0≤u≤7 and 0≤v≤2π3 and f(x,y,z)=x2+y2+z2. Set up the sur
Bad White [126]

Looks like you have most of the details already, but you're missing one crucial piece.

\sigma is parameterized by

\vec r(u,v)=\langle u\cos3v,u\sin3v,v\rangle

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\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}=\left\langle\sin3v,-\cos3v,3u\right\rangle

with norm

\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|=\sqrt{\sin^23v+(-\cos3v)^2+(3u)^2}=\sqrt{9u^2+1}

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\displaystyle\iint_\sigma f(x,y,z)\,\mathrm dA=\boxed{\int_0^{2\pi/3}\int_0^7(u^2+v^2)\sqrt{9u^2+1}\,\mathrm du\,\mathrm dv}

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