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3 years ago

Find the two partial products in the multiplication problem.

Mathematics

1 answer:

Mumz [18]3 years ago

4 0

Answer:

690 and 6,900

Step-by-step explanation:

230

x 33

______

690

+ 6,900

________

7590

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Which of the following statements about points are false?

vagabundo [1.1K]

Answer:

their sizes vary

Step-by-step explanation:

their sizes vary

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3 years ago

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Write the number seven and one - third as a decimal rounded to the nearest hundredth

bagirrra123 [75]

Well you know you keep the 7. 1/3 well you see it as .3333 so just go 7.33 because 7.333 and since it's a 3 you keep it.

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3 years ago

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Is 14/35 and 21/42 proportional

PIT_PIT [208]

1.Simplified each one
2/5 (both divided by 7) , 1/2 (divided by 21)
2.Make them into integer
(2/5 )*(2/2)=4/10 , (1/2)*(5/5)=5/10
Now the dominators are the same ,you can just compare the numerators. It is 4:5

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3 years ago

Harry is trying to solve the equation 0 = 2x2 − x − 6 using the quadratic formula. He has made an error in one of the steps belo

bija089 [108]

<h3><u>Given</u> - </h3>

➙ a quadratic equation in which Harry lagged due to an error made by him, 2x² - x - 6= 0

<h3><u>To solve</u> - </h3>

➙ the given quadratic equation.

<h3><u>Concept applied</u> - </h3>

➙ We will apply the quadratic formula as given in the question. So, let's study about quadratic equation first because we are supposed to apply the formula in equation.

What is quadratic equation?

➙ A quadratic equation in the variable x is an equation of the form ax² + bx + c = 0, where a, b, c are real numbers, a ≠ 0.

Now, what is quadratic formula?

➙The roots of a quadratic equation ax + bx + c = 0 are given by $\sf{\:\frac{-b \pm\: \sqrt {b ^ 2 - 4ac}}{2a}}$ provided b - 4ac ≥ 0.

<h3><u>Solution</u> - </h3>

here as per the given quadratic equation,

a = 2, b = -1 and c = -6

putting in the formula,

$\implies\sf{x=\frac{-(-1) \pm\: \sqrt {(-1)^2 - 4(2)(-6)}}{2(2)}}$

$\implies\sf{x=\frac{1 \pm\: \sqrt {1+48}}{4}}$

$\implies\sf{x=\frac{1 \pm\: \sqrt {49}}{4}}$

$\implies\sf{x=\frac{1 \pm\: 7}{4}}$

Solving one by one,

$\implies\sf{x=\frac{1 + \: 7}{4}}$

$\implies\sf{x=\frac{8}{4}}$

$\implies{\boxed{\bf{x=2}}}$

________________

$\implies\sf{x=\frac{1 - \: 7}{4}}$

$\implies\sf{x=\frac{-6}{4}}$

$\implies{\boxed{\bf{x=\frac{-3}{2}}}}$

________________________________

<em><u>Note</u> - Hey dear user!! You haven't provided the solution which was solved by Harry (A.T.Q). Please go through the solution as it will help you to find the error done by Harry.</em>

Hope it helps!! (:

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2 years ago

What would this One be??

inn [45]

Answer:

the pre-image and the image are congruent

Step-by-step explanation:

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3 years ago

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