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Ksivusya [100]
2 years ago
7

M = 2; b=3 using y-intercept how do i solve

Mathematics
1 answer:
mash [69]2 years ago
6 0

The slope-intercept form:

y=mx+b

m - slope

b - y-intercept

We have m = 2 and b = 3. Substitute:

y=2x+3

You might be interested in
(a) Find the three-digit number that increases by 30% when each of its
Elden [556K]

Step-by-step explanation:

So a three digit number can be expressed as: 100a + 10b + c where a is the third digit, b is the second digit, and c is the first digit. Or in other words a is the hundreds place, b is the tens place, and c is the ones place. When something "increases" by 30%, it is 130% it's original value, and to calculate how much that is, you simply convert 130% to a decimal by dividing by 100, which gives you 1.30. And since all the digits are increased by 1, you have the equation:

100(a+1) + 10(b+1) + 1(c+1) = 1.30(100a+10b+c)

Distribute the multiplication on the left side:

100a+100+10b+10+c+1=1.30(100a+10b+c)

Distribute the multiplication on the right side:

100a+100+10b+10+c+1=130a+13b+1.3c

Add like terms on the left side:

100a+10b+c+111=130a+13b+1.3c

Subtract 100a, 10b, and c from both sides

111=30a+3b+0.3c

So "technically" you can just plug in any two values, and then solve for the last value, but since you have a 3 digit number, you have the restriction of a < 10, b < 10, and c < 10, and also a, b, and c, should only be integers and all have the same sign or it wouldn't be a 3 digit number.

So let's start with a, since it has the highest coefficient, well you can fit 30 into 111, 3 times without going over so that's the first value

111 = 30(3) + 3b + 0.3c

111 = 90 + 3b + 0.3c

Now subtract the 90 from both sides

21=3b+0.3c

Well 3 can fit into 21, 7 times!

21 = 3(7) + 0.3c

21 = 21 + 0.3c

subtract 21 from both sides

0 = 0.3c

and now obviously c is 0, if you want you can divide both sides by 0.3 but it's a bit redundant

c = 0

This gives you the three values, a=3, b=7, c=0. which is the number 370. Now let's double check. Adding 1 to each digit would give you 481 and 481/370 = 1.3, so it is correct!

part b:

So to prove there is no three digit number, is to realize there is no solution, given the restriction or integers, greater than or equal to 0, and less than 10, and all of them must have the same sign.

So let's start with the same equation except this time instead of 1.3 it's 1.4

100(a+1) + 10(b+1) + 1(c+1) = 1.40(100a+10b+c)

Distribute on the left side;

100a+100+10b+10+c+1=1.40(100a+10b+c)

Distribute on the right side:

100a+100+10b+10+c+1=140a + 14b + 1.4c

Add like terms on left side:

100a + 10b + c + 111 = 140a + 14b + 1.4c

Subtract 100a, 10b, and c from both sides:

111 = 40a + 4b + 0.4c

Now to do the same process, let's start by finding how many times we can fit 40 into 111, and if you're wondering why we start with 40, it's because let's say for example I just say, I can fit another 40 into it, but I decide not to, and let b do that, well even if it's just 40, b will have be at least 10, which does not fit our restrictions, so you have to fit as many 40's into the number first then go the other numbers.

So only 2 40's can fit in 111 without going over the value

111 = 40(2) + 4b + 0.4c

Subtract 80 from both sides

31=4b+0.4c

4 can fit into 31, 7 times

31 = 4(7) + 0.4c

31 = 28 + 0.4c

subtract 28 from both sides

3 = 0.4c

divide both sides by 0.4

7.5 = c.

Since c is not an integer there is no 3 digit number that exists that increases by 40% whenever you increase it by 1.

7 0
2 years ago
Find the HCF of 27, 63, 54 using prime factorization method.
Step2247 [10]

Answer:

27 = 3 , 3, 3

63= 3 , 3, 7

54= 3 , 3, 3, 2

HCF OF 27, 63 AND 54 = 3 X 3 = 9

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7 0
2 years ago
Divide thirty-one point five by ten
Nutka1998 [239]
3.15 will be your answer i am very sure of that
5 0
2 years ago
Read 2 more answers
Carla wants the total weight of the bags to be four pounds. If she can only pick one more bag, which bag weight should she pick?
pychu [463]

Answer:

1/8

Step-by-step explanation:

To find which bag weight Carla needs, the first step is to find the total weight of the bags shown in the line plot.

There are three -pound bags.

There are six -pound bags.

There are four -pound bags.

Multiply the weight and number of each bag to find the total weight of each different weight bag.

Now, add the three totals.

Finally, subtract the total weight from four pounds in order to find which weight Carla needs.

So, Carla should pick one -pound bag of candy to total four pounds.

4 0
2 years ago
A group of tenth grade students responded to a survey that was asked which Math course they were currently enrolled in. The surv
ale4655 [162]

Answer:

C.

Step-by-step explanation:

The bottom-right most cell tells us that the total number of students that responded to the survey is 310 students.

To find the answer, we can go through each choice.

A. Females taking Geometry

Row 1 Column 2 tells us that 53 females are taking geometry. 53/310 is about 17%.

B. Females taking Algebra II.

Row 1 Colume 3 tells us that 62 females are taking Algebra II. 62/310 is 20%.

C. Males taking Geometry.

Row 2 Colume 2 tells us that 59 males are taking Geometry. 59/310 is about 19%. Choice C is correct.

D. Males taking Algebra I.

44 out of the total 310 respondents are male and is taking Algebra I. 44/310 is about 14%.

4 0
3 years ago
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