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3 years ago

M = 2; b=3 using y-intercept how do i solve

Mathematics

1 answer:

mash [69]3 years ago

6 0

The slope-intercept form:

$y=mx+b$

m - slope

b - y-intercept

We have m = 2 and b = 3. Substitute:

$y=2x+3$

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A survey of 35 people was conducted to compare their self-reported height to their actual height. The difference between reporte

Over [174]

Answer:

The test statistic is t = 3.36.

Step-by-step explanation:

You're testing the claim that the mean difference is greater than 0.7.

At the null hypothesis, we test if the mean difference is of 0.7 or less, that is:

$H_0: \mu \leq 0.7$

At the alternate hypothesis, we test if the mean difference is greater than 0.7, that is:

$H_1: \mu > 0.7$

The test statistic is:

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, s is the standard deviation of the sample and n is the size of the sample.

0.7 is tested at the null hypothesis:

This means that $\mu = 0.7$

A survey of 35 people was conducted to compare their self-reported height to their actual height.

This means that $n = 35$

From the sample, the mean difference was 0.95, with a standard deviation of 0.44.

This means that $X = 0.95, s = 0.44$

Calculate the test statistic

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{0.95 - 0.7}{\frac{0.44}{\sqrt{35}}}$

$t = 3.36$

The test statistic is t = 3.36.

3 0

3 years ago

Find the solution set of the following quadratic equations using the quadratic formula.

oksian1 [2.3K]

Answer:

<h3> 1) $x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2$ </h3><h3> 2) $x_1=-\dfrac13\,,\quad x_2=-3$ </h3>

Step-by-step explanation:

$x^2 - 7x + 9 = 0\quad\implies\quad a=1\,,\ b = -7\,,\ c=9\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-(-7)\pm\sqrt{(-7)^2-4\cdot1\cdot9}}{2\cdot1}=\dfrac{7\pm\sqrt{49-36}}2\\\\x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2$

<h3>2)</h3><h3> $3x^2 + 10x=-3\\\\3x^2+10x+3=0\quad\implies\quad a=3\,,\ b =10\,,\ c=3\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-10\pm\sqrt{10^2-4\cdot3\cdot3}}{2\cdot3}= \dfrac{-10\pm\sqrt{100-36}}6\\\\x_1=\dfrac{-10+\sqrt{64}}6=\dfrac{-10+8}6=-\dfrac13\,,\qquad x_2=\dfrac{-10-8}6=-3$ </h3>

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3 years ago

Two times a number plus six is eight

AleksandrR [38]

Answer:

Why:

2 × 1 + 6

2 + 6 = 8

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3 years ago

it takes 3 4/5 of kilometers of thread to make 2 3/6 boxes of shirts. how many kilometers of thread will it take to make 5 boxes

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7 3/5 for 5 kilometers

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What is the domain of the graph for the data set?

WINSTONCH [101]

Answer:

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Step-by-step explanation:

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