1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
yulyashka [42]
3 years ago
14

Tenemos 2000 baldosascon las que nos proponrmos embaldosar dos habitaciones.Para la 1ª gastamos 3/5 de ellas,y con la 2ª,3/4de l

as que qudaron.¿Cuántas utilizamos para cada habitación y cuántas sobraron?
Mathematics
1 answer:
Setler79 [48]3 years ago
6 0

Answer:

En la primera habitación son usadas 1200 baldosas.

En la segunda habitación son usadas 600 baldosas.

Sobraron 200 baldosas.

Step-by-step explanation:

Tienes 2000 baldosas, con las que se propone embaldosar dos habitaciones.

Para la primera habitación se han gastado \frac{3}{5} de las baldosas. Esto se expresa como:

\frac{3}{5}*2000

Para multiplicar una fracción por un número entero, el número entero n se puede escribir como la fracción \frac{n}{1}. Luego se multiplica los numeradores y denominadores. En este caso:

\frac{3}{5}*2000=\frac{3}{5}*\frac{2000}{1} =\frac{3*2000}{5*1} = \frac{6000}{5}

Para reducir la fraccion, divide 40 entre 10

\frac{6000}{5} = 6000 ÷5= 1200

Entonces <u><em>en la primera habitación son usadas 1200 baldosas.</em></u> Por lo que las que quedan se calcula como:

2000 - 1200= 800 baldosas

De esta cantidad de baldosas que quedaron, \frac{3}{4} son usadas para embaldosar la segunda habitación.  Esto se expresa como:

\frac{3}{4}*800

Resolviendo de igual manera que en el caso de la primer habitación se obtiene:

\frac{3}{4}*800=\frac{3}{4}*\frac{800}{1} =\frac{3*800}{4*1} =\frac{2400}{4}= 2400 ÷ 4= 600

Entonces <u><em>en la segunda habitación son usadas 600 baldosas.</em></u> Por lo que, teniendo en cuenta que se tenían 800 baldosas que quedaron de la primera habitación, las baldosas restantes se calculan como:

800 - 600= 200 baldosas

<u><em>Sobraron 200 baldosas.</em></u>

You might be interested in
Which describes the process that could be used as the first step in solving this equation? 6x = 4 + 5(x + 8) A) Combine like ter
ra1l [238]

Answer:

It is B.

Step-by-step explanation:

The first step  would be to use the Distributive Property  to multiply  5(x + 8).

So the second line would be: 6x = 4 + 5x + 40.

3 0
3 years ago
Read 2 more answers
Tanay purchased a pair of shoes for $67.45 and a new shirt for $18.78. How much money does he have left if he started with $100?
babymother [125]
The answer is $13.77
explanation is 67.45 - 18.78=48.67 and 100 - 48.67= $13.77
7 0
3 years ago
A store plans to sell two different game consoles, the YuuMi and the ZBox. The store’s wholesale cost for a YuuMi is $250, and t
strojnjashka [21]

9514 1404 393

Answer:

  • Constraints: x + y ≤ 250; 250x +400y ≤ 70000; x ≥ 0; y ≥ 0
  • Objective formula: p = 45x +50y
  • 200 YuuMi and 50 ZBox should be stocked
  • maximum profit is $11,500

Step-by-step explanation:

Let x and y represent the numbers of YuuMi and ZBox consoles, respectively. The inventory cost must be at most 70,000, so that constraint is ...

  250x +400y ≤ 70000

The number sold will be at most 250 units, so that constraint is ...

  x + y ≤ 250

Additionally, we require x ≥ 0 and y ≥ 0.

__

A profit of 295-250 = 45 is made on each YuuMi, and a profit of 450-400 = 50 is made on each ZBox. So, if we want to maximize profit, our objective function is ...

  profit = 45x +50y

__

A graph is shown in the attachment. The vertex of the feasible region that maximizes profit is (x, y) = (200, 50).

200 YuuMi and 50 ZBox consoles should be stocked to maximize profit. The maximum monthly profit is $11,500.

4 0
3 years ago
A leprechaun places a magic penny under a​ girl's pillow. The next night there are 2 magic pennies under her pillow. Each night
viktelen [127]

Answer:

$665.36

Step-by-step explanation:

2^16 or...

2x2x2x2x2x2x2x2x2x2x2x2x2x2x2x2 = 66536 pennies

3 0
3 years ago
Jason complete 5/8 of his test and 10/25 of his homework. What fraction of his homework does he still need to complete?
sineoko [7]

Answer:

3/4

Step-by-step explanation:

Because the total homework would be 25/25

\frac{25}{25}-\frac{10}{25} =\frac{15}{25}

15/20 can be reduced to 3/4

4 0
3 years ago
Other questions:
  • 3. If the line tangent to the graph of the function f at the point (1,7) also passes through the point
    8·1 answer
  • What is the distance between (-5,-5) and (-9,-2)
    15·1 answer
  • Six more than the product of a number and 3 equals 7. Translate the sentence into an equation.
    10·1 answer
  • Help please?<br> Which graph can be used to find the solution(s) to x2 – 1 = x + 1?
    8·2 answers
  • What is the absolute value of Point B labelled on the number line? A number line with point A at coordinate negative 2.2, point
    13·1 answer
  • Can I get help on 1-20 please
    6·1 answer
  • according to a label there are 25 calories per turkey lunchmeat. How many calories are there in 2.5 servings?​
    14·2 answers
  • Derrick has a very long rope. He used 3/8 of it to make some outdoor structures. He cut the remainder up into 15 equal short rop
    8·1 answer
  • Is (8, 3) a solution to the system?<br> - x + 4y = 4<br> - x + 3y = 1
    9·1 answer
  • Help im giving sm points
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!