Answer:
a) 29
b) 0
c) 7
d) 3/8
Step-by-step explanation:
Whenever you're facing a clock maths problem, the solution always have to be < to the number of hours in the given clock. If it's > the number of hours of the given clock, you subtract the number of hours until you get a result <= the number of clock hours.
If the result is negative, you add the clock hours.
a) 21 - 33 = -12 , so -12 + 41 = 29
b) 13 * 4 = 52, then do 52 - 52 = 0, since answer has to be < 52.
c) 11+19 = 30, 30 - 23 = 7
d) 3/8 = 3/8, since 3/8 <= 15, you're also fine.
-4x^4 - 15x^2 + 1 - 19/x^2 is your answer
Hope I helped :)
Answer:
6^3= 216
4^4=256
216*256=55296
Step-by-step explanation:
no1 should sue u boo lm.fao
Answer:
A, B, D, F
Step-by-step explanation:
Matrix operations require that the matrix dimensions make sense for the operation being performed.
Matrix multiplication forms the dot product of a row in the left matrix and a column in the right matrix. That can only happen if those vectors have the same dimension. That is the number of columns in the left matrix must equal the number of rows in the right matrix.
Matrix addition or subtraction operates on corresponding terms, so the matrices must have the same dimension.
The transpose operation interchanges rows and columns, so reverses the dimension numbers. It is a defined operation for any size matrix.
<h3>Defined operations</h3>
A. CA ⇒ (4×7) × (7×2) . . . . defined
B. B -A ⇒ (7×2) -(7×2) . . . . defined
C. B -C ⇒ (7×2) -(4×7) . . . undefined
D. AB' ⇒ (7×2) × (2×7) . . . . defined
E. AC ⇒ (7×2) × (4×7) . . . undefined
F. C' ⇒ (7×4) . . . . defined
