Answer:
(x/5) - 4
Step-by-step explanation:
You want four less than the quotient of x and 5 so you make x/5 a single term. Then subtract 4
That would be DF is congruent to DE ( first choice)
( they are both = sqrt(2^2 + 3^2)
Here the only limitation on the domain exists when the denominator is equal to zero, as division by zero has no meaning and is not "allowed" because of its meaninglessness. :)
Factor the denominator to find the excluded values of x...
3x^2+5x-12
3x^2+9x-4x-12
3x(x+3)-4(x+3)
(3x-4)(x+3)
So x CANNOT equal 4/3 or -3 (all other real values of x are part of the domain) so the domain is:
x=(-oo, -3),(-3, 4/3),(4/3, +oo)
Answer:
The first 5 terms are;
-2, 2, 13,38 and 91
Step-by-step explanation:
Here, we want to write the first 5 terms of the sequence.
We already have the first term as 1
Now, we need the 2nd term
Putting two in place of n, we have ;
2f(1) + 3n
= 2(-2) + 3(2) = -4 + 6 = 2
For the 3rd term, put 3 in place of n
2f(2) + 3(3)
sine f(2) = 2, we have
2(2) + 9 = 4+ 9 = 13
For the fourth term, put 4 in place of n, we have
2f(3) + 3(4)
since f(3) = 13
we have; 2(13) + 12 = 26 + 12 = 38
For the 5th term, put 5 in place of n, we have
2f(4) + 3(5)
since f(4) = 38, we have
2(38) + 15 = 76 + 15 = 91
Answer:
20
Step-by-step explanation:
Side of the square = hypotenuse of triangle = √(4² + 2²)=√(16 + 4)=√(20)
Area of a square = (side)² = (√20)² = 20 units²
