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ollegr [7]
2 years ago
13

PLZZZZZZZZZZZZZZZZ HELP ME i begging YOUUUUU !!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
ElenaW [278]2 years ago
5 0

Answer:

answer is 3 = free points B)

Step-by-step explanation:

gizmo_the_mogwai [7]2 years ago
3 0

Answer:

The answer is -3 for B. and idk for A.

Step-by-step explanation:

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43 and 962 ten thousandths form
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43.0962 is ten thousandths in standard form
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3 years ago
Which value of P and Q result in an equation with no solutions? 83x+P=83x+Q
alekssr [168]

There is no number I can think of that would make the statement untrue.

The result of this when you subtract 83x from both sides leaves you with P = Q.

Unless you know differently, the equation says that P must equal Q no matter what x is. If there is such a condition, it is not obvious.

3 0
3 years ago
Which expression is equivalent to the some 30 + 12
Alecsey [184]

Answer:

give a picture

Step-by-step explanation:

5 0
3 years ago
Please help
iren2701 [21]
For question 1:
1% = 120 ÷ 100 = 1.2
15% = 1.2 × 15 = 18
So, 15% of 120 is 18

For question 2:
68.4 ÷ 72 = 0.95
0.95 × 100 = 95%
So, the percentage is 95%

For question 3,
1% = 12.5 ÷ 8 = 1.5625
100% = 1.5625 × 100 = 156.25
So, 8% of 12.5 is 156.25.

For question 4,
1% = 48 ÷ 40 = 1.2
100% = 1.2 × 100 = 120
So, 40% of 48 is 120.

For question 5,
1% = 195 ÷ 100 = 1.95
62.5% = 1.95 × 62.5 = 121.875
So, 62.5% of 195 is 121.875
8 0
2 years ago
What is the derivative of the following function? f(x) = 4x^6/cos^5(x)
KIM [24]

Answer:

f'(x) = \frac{24x^{5} \cos x + 20x^{6}\sin x}{\cos^{6}x }

Step-by-step explanation:

We have to find the derivative of the following function:

f(x) = \frac{4x^{6} }{\cos^{5} x }

Now, differentiating both sides with respect to x we get,

f'(x) = \frac{\cos^{5}x (24x^{5}) - 4x^{6}(5\cos^{4}x )(- \sin x)}{(\cos^{5}x )^{2}}

⇒ f'(x) = \frac{ 24x^{5} \cos x + 20 x^{6}\sin x}{\cos^{6}x } (Answer)

{Since, we know that, \frac{d(mx^{n} )}{dx} = m \times n x^{(n - 1)} and \frac{d(\cos^{n} x)}{dx} = n \cos^{(n - 1)} x(- \sin x) }

5 0
3 years ago
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