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3 years ago

PLZZZZZZZZZZZZZZZZ HELP ME i begging YOUUUUU !!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

ElenaW [278]3 years ago

5 0

Answer:

answer is 3 = free points B)

Step-by-step explanation:

gizmo_the_mogwai [7]3 years ago

3 0

Answer:

The answer is -3 for B. and idk for A.

Step-by-step explanation:

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I need help on this question I’m confused I think a &b are the same and c &d are different but I’m not to sure !

Nina [5.8K]

<h3>Answer: They're all the same</h3>

====================================================

Reason:

$2^6$ means we have 6 copies of "2" multiplied out as shown in choice B. That explains how A and B are the same, and we can say

$2^6 = (2*2*2)*(2*2*2)$

The parenthesis are optional, but I find they're handy to count the '2's easier.

----------------

Now notice that

$2^3 = 2*2*2$

So,

$2^6 = (2*2*2)*(2*2*2)\\\\2^6 = (2^3)*(2^3)\\\\2^6 = (2^3)^2\\\\$

The last step is possible because we have two copies of $2^3$ multiplied together.

This shows that choice C is equivalent to A and B.

-------------------

Lastly,

$2^6 = (2*2*2)*(2*2*2)\\\\2^6 = (2*2)*(2*2)*(2*2)\\\\2^6 = (2^2)*(2^2)*(2^2)\\\\2^6 = (2^2)^3\\\\$

The jump to the last step is possible because we have three copies of $2^2$ multiplied together.

This shows choice D is equivalent to the others.

All four expressions are the same.

They represent different ways to say the same number. That number being 64.

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Factor completely 3x − 12.<br> 3(x − 4)<br> 3(x + 4)<br> 3x(−12)<br> Prime

joja [24]

The answer is 3x(-12) I 'am 100% show..

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Kruka [31]

Hello, please consider the following.

$\displaystyle \begin{aligned} \int\limits^x {5sin(5t)sin(t)} \, dt &= -\int\limits^x {5sin(5t)} \, d(cos(t))\\ \\&=-[5sin(5t)cos(t)]+ \int\limits^x {25cos(5t)cos(t)} \, dt\\\\&=-5sin(5x)cos(x)+ \int\limits^x {25cos(5t)} \, d(sin(t))\\ \\&=-5sin(5x)cos(x)+[25cos(5t)sin(t)]+ \int\limits^x {25sin(5t)sin(t)} \, dt\\\\&=-5sin(5x)cos(x)+25cos(5x)sin(x)+ \int\limits^x {(25*5)sin(5t)sin(t)} \, dt\end{aligned}$