You reject the Null Hypothesis only if the p-value is less than alpha.
p < 0.01
To find the p-value, you need to look up test value 2.07 in a standard normal table. The p-value is probability that Z > 2.07. For a two-tailed test, you include both positive and negative cases. |Z| > 2.07.
When you look up 2.07 you get about 0.98.
This means there is about 2% chance Z > 2.07 or 4% chance |Z| > 2.07.
For the two-tailed test we use p = 0.04
.04 > .01
Therefore we do Not reject the Null Hypothesis.
<span>Given cotA + cotB + cotC = sqrt3
to prove triangle ABC is equilateral
we prove this by assuming ABC to be equialteral and establishing the truth
of the statement cotA + cotB + cotC =sqrt3
since ABC is equialteral angleA=angleB=angleC=60 degrees
cotA=cotB=CotC = cot60= 1/sqrt3
therefore cotA + cotB + cotC = 1/sqrt3 + 1/sqrt3 + 1/sqrt3
=3/sqrt3
=sqrt3 which is equal to the RHS ( right hand side) of the expression
hence our assumption that ABC is equilateral is true</span>
Answer: For example, in order to explain why 1/3 + 1/4 = 7/12, we considered the task of dividing 7 apples between 12 boys under the restriction that an apple ... How many halves are in the whole? ... 1 = 3 × 1/3, 2 = 6 × 1/3, 3 = 9 × 1/3, 4 = 12 × 1/3.
Step-by-step explanation:
boom your nice wanna be my friend
<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em> </em><em>⤴</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>.</em>
Answer:
B.
Step-by-step explanation:
The symbol between JK and LM mean that they are perpendicular, it is, that at their intersection 90 degrees angles are formed (those are right angles). So, the correct option here is option B. JK and LM meet at a right angle.
Here I attach a dray of how an intersection like this must look like. I hope it is helpful for you. In the draw four right angles are formed, however, this is not necessary, coul be only one or two depending on the length of the lines segments.
