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schepotkina [342]
3 years ago
7

Somebody please help me :)​

Mathematics
1 answer:
aleksandrvk [35]3 years ago
6 0

Answer:

(5,7.5) (12,18) (18,27)

Step-by-step explanation:

It costs $1.50 per cupcake.

y = 1.5x, where x is the amount of cupcakes and y is the amount of money in dollars.

7.5 = 1.5 times 5

18 = 1.5 times 12

27 = 1.5 times 18

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Find f(a), f(a+h), and<br> 71. f(x) = 7x - 3<br> f(a+h)-f(a)<br> h<br> if h = 0.<br> 72. f(x) = 5x²
Leni [432]

Answer:

71. \ \ \ f(a) \  = \  7a \ - \ 3; \ f(a+h) \  =  \ 7a \ + \ 7h \ - \ 3; \ \displaystyle\frac{f(a+h) \ - \ f(a)}{h} \ = \ 7

72. \ \ \ f(a) \  = \  5a^{2}; \ f(a+h) \  =  \ {5a}^{2} \ + \ 10ah \ + \ {5h}^{2}; \ \displaystyle\frac{f(a+h) \ - \ f(a)}{h} \ = \ 10a \ + \ 5h

Step-by-step explanation:

In single-variable calculus, the difference quotient is the expression

                                              \displaystyle\frac{f(x+h) \ - \ f(x)}{h},

which its name comes from the fact that it is the quotient of the difference of the evaluated values of the function by the difference of its corresponding input values (as shown in the figure below).

This expression looks similar to the method of evaluating the slope of a line. Indeed, the difference quotient provides the slope of a secant line (in blue) that passes through two coordinate points on a curve.

                                             m \ \ = \ \ \displaystyle\frac{\Delta y}{\Delta x} \ \ = \ \ \displaystyle\frac{rise}{run}.

Similarly, the difference quotient is a measure of the average rate of change of the function over an interval. When the limit of the difference quotient is taken as <em>h</em> approaches 0 gives the instantaneous rate of change (rate of change in an instant) or the derivative of the function.

Therefore,

              71. \ \ \ \ \ \displaystyle\frac{f(a \ + \ h) \ - \ f(a)}{h} \ \ = \ \ \displaystyle\frac{(7a \ + \ 7h \ - \ 3) \ - \ (7a \ - \ 3)}{h} \\ \\ \-\hspace{4.25cm} = \ \ \displaystyle\frac{7h}{h} \\ \\ \-\hspace{4.25cm} = \ \ 7

               72. \ \ \ \ \ \displaystyle\frac{f(a \ + \ h) \ - \ f(a)}{h} \ \ = \ \ \displaystyle\frac{{5(a \ + \ h)}^{2} \ - \ {5(a)}^{2}}{h} \\ \\ \-\hspace{4.25cm} = \ \ \displaystyle\frac{{5a}^{2} \ + \ 10ah \ + \ {5h}^{2} \ - \ {5a}^{2}}{h} \\ \\ \-\hspace{4.25cm} = \ \ \displaystyle\frac{h(10a \ + \ 5h)}{h} \\ \\ \-\hspace{4.25cm} = \ \ 10a \ + \ 5h

4 0
2 years ago
HI I really need help with this its in the picture
Hitman42 [59]
<h3>Answer:  24a^4 + 36a^3 + 12a^2</h3>

Explanation:

The blue rectangle has area of 4a^2*6a^2 = 24a^4

The red rectangle has area 4a^2*9a = 36a^3

The green rectangle has area 4a^2*3 = 12a^2

The total area is 24a^4 + 36a^3 + 12a^2

7 0
2 years ago
The fox population in a certain region has a continuous growth rate of 7 percent per year. It is estimated that the population i
rjkz [21]

Answer:

P(t) = 14300e^0.07t

Step-by-step explanation:

Let :

Population as a function of years, t = P(t) ;

Growth rate, r = 7%

Estimated population on year 2000 = Initial population = 14300

The given scenario can be modeled using an exponential function as the change in population is based in a certain percentage increase per period.

P(t) = Initial population*e^rt

P(t) = 14300*e^(0.07t)

P(t) = 14300e^0.07t

Where, t = number of years after year 2000.

7 0
3 years ago
Plsssss Answer
Bezzdna [24]

50 per share hope this helped

6 0
3 years ago
Solve for equation for ex in term of c 2/3(x+1/2) - 1/4=5/2
serg [7]

\dfrac{2}{3}\left(x+\dfrac{1}{2}\right)-\dfrac{1}{4}=\dfrac{5}{2}\qquad|\text{use distributive property}\\\\\dfrac{2}{3}x+\dfrac{2}{3}\cdot\dfrac{1}{2}-\dfrac{1}{4}=\dfrac{5}{2}\\\\\dfrac{2}{3}x+\dfrac{1}{3}-\dfrac{1}{4}=\dfrac{5}{2}\qquad|\text{multiply both sides by LCM(2,\ 3,\ 4)=12}\\\\12\cdot\dfrac{2}{3}x+12\cdot\dfrac{1}{3}-12\cdot\dfrac{1}{4}=12\cdot\dfrac{5}{2}\\\\4\cdot2x+4-3=6\cdot5\\\\8x+1=30\qquad|\text{subtract 1 from both sides}\\\\8x=29\qquad|\text{divide both sides by 8}\\\\x=\dfrac{29}{8}

4 0
3 years ago
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