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3 years ago

Pleaaasseee help!!! BRAINLIEST FOR CORRECT ANSWER!! What is the transformation rule for a translation 3 units right?

Mathematics

1 answer:

garri49 [273]3 years ago

4 0

Answer:

Rule: replace x by x - a where a is the number of units that you want to move right. a must be greater than 0. x - - a would move left.

Step-by-step explanation:

You want f(x) to move 3 units to the right.

That would mean that x would be replaced by x - 3. Just to be sure let's try it.

Suppose you have f(x) = x^2 + 6x + 5 It is graphed as the red line
Now suppose you want to move 3 units right.
It would replaced like f(x - 3) = (x - 3)^2 + 6(x - 3) + 5 which is the blue line
Notice nothing else is changed. The blue line looks exactly like the red line except that it is shifted 3 units to the right.

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Show that ( 2xy4 + 1/ (x + y2) ) dx + ( 4x2 y3 + 2y/ (x + y2) ) dy = 0 is exact, and find the solution. Find c if y(1) = 2.

fredd [130]

$\dfrac{\partial\left(2xy^4+\frac1{x+y^2}\right)}{\partial y}=8xy^3-\dfrac{2y}{(x+y^2)^2}$

$\dfrac{\partial\left(4x^2y^3+\frac{2y}{x+y^2}\right)}{\partial x}=8xy^3-\dfrac{2y}{(x+y^2)^2}$

so the ODE is indeed exact and there is a solution of the form $F(x,y)=C$ . We have

$\dfrac{\partial F}{\partial x}=2xy^4+\dfrac1{x+y^2}\implies F(x,y)=x^2y^4+\ln(x+y^2)+f(y)$

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With $y(1)=2$ , we have

$8+\ln9=C$

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3 years ago

What is 6112 inches squared?

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3 years ago

Read 2 more answers

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Allisa [31]

Step-by-step explanation:

the difference is the previous term multiplied by 4 to get the next term

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Hope that helps :)

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3 years ago

Select all the distribution shapes for which it is most often appropriate to use the mean .

goblinko [34]

The distribution shape that tells us for which it is best to use the mean is the skewed.

This is the term that is used to refer to the average score that exists in a data set.

In the question, these are the reasons why the other options are not correct

When we say Bimodal we are talking about the 2 modes that are in a symmetric distribution. This has nothing to do with the mean

The bell shape has to do with how the normal distribution is when it is drawn. It would create a bell shape hence the mean is not useful.

symmetric has to do with the fact that there are mirror images when the vertical line is drawn in the distribution.

Uniformed shapes tells us that the classes are made up of the same frequency all through.

The skewed shape is what tells us if the median is more or if it is less.

Hence we have the answer that the distribution shapes for which it is most often appropriate to use the mean is the skewed.