Y=1
Y=1 because then it is saying that the line is touching the y axes at 1
Answer:
I'm pretty sure that it's just the negatives of the coordinates, (-3,-4) (-3,-1) (-5,-1). I don't know for sure tho, sorry if its wrong.
Step-by-step explanation:
Yes it’s right for this problem
Answer:
2 real solutions
Step-by-step explanation:
Remember this messy thing?

The <em>quadratic formula</em>, as it's called, gives us the roots to any quadratic equation in standard form (ax² + bx + c = 0). The information on the <em>type</em> of roots is contained entirely in that bit under the square root symbol (b² - 4ac), called the <em>discriminant</em>. If it's non-negative, we'll have <em>real</em> roots, if it's negative, we'll have <em>complex roots</em>.
For our equation, we have a discrimant of (-3)² - 4(6)(-4) = 9 + 96 = 105, which is non-negative, so we'll have real solutions, and since quadratics are degree 2, we'll have exactly 2 real solutions.
Answer:
-36x^2+1
Step-by-step explanation:
(1+6x)(1-6x)
= 1^2(6x)^2
= -36x^2+1