Please help me please will give brainly

Mathematics

1 answer:

JulijaS [17]3 years ago

7 0

its b

Step-by-step explanation:

not really sure hope you get this right im sooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo sorrryyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyy i9f you get this wrong

You might be interested in

If two equations have the same slope, are their corresponding lines always the same when graphed?

torisob [31]

Answer:

see the explanation

Step-by-step explanation:

we know that

If two lines have the same slope, then the lines are parallel.

If two parallel lines have the same y-intercept or any point in common, then the lines are identical when graphed

If two parallel lines have different y-intercept, then the lines are different parallel lines when graphed

6 0

3 years ago

How many solutions are there to the equation below?

Reil [10]

I think it’s B I’m not to sure but I know someone with that exact solution

5 0

3 years ago

What is the coefficient in the following expression: 5 + 3x + (-3) A) 5 B) 3 C) x D) -3

Crazy boy [7]

Answer:

B) 3

Step-by-step explanation:

If it was right please mark me brainleist.

6 0

2 years ago

Plz solve this problem of trigonometry i am an aakashian

makkiz [27]

Step-by-step explanation:

$\bf L.H.S = \tt \dfrac{sec\: \theta + tan \: \theta - 1}{tan \: \theta - sec \: \theta + 1} \\ \\$

$: \implies \tt \dfrac{\frac{1}{cos \: \theta} + \frac{sin \: \theta}{cos \: \theta} - 1}{ \frac{sin \: \theta}{cos \: \theta} - \frac{1}{cos \: \theta} + 1 } \: = \dfrac{1 + sin \: \theta - cos \: \theta}{sin \: \theta + cos \: \theta} \\ \\$

$: \implies \tt\dfrac{ sin \: \theta - (cos \: \theta - 1)}{sin \: \theta + (cos \: \theta - 1)} \: \times \: \dfrac{ sin \: \theta - (cos \: \theta - 1)}{sin \: \theta - (cos \: \theta - 1)} \\ \\$

$: \implies \tt\dfrac{ sin^{2} \: \theta + cos^{2} \: \theta + 1 - 2 \: cos \: \theta - 2 \: sin \: \theta \: (cos \: \theta - 1)}{sin^{2} \: \theta - (cos \: \theta - 1)^{2} } \\ \\$

$: \implies \tt\dfrac{1 + 1 - 2 \: cos \: \theta - 2 \: sin \: \theta \: cos \: \theta + 2 \: sin \: \theta}{sin^{2} \: \theta + cos^{2} \: \theta - 1 + 2 \: cos \: \theta } \\ \\$

$: \implies \tt\dfrac{2 - 2 \: cos \: \theta - 2 \: sin \: \theta \: cos \: \theta + 2 \: sin \: \theta}{sin^{2} \: \theta + cos^{2} \: \theta - sin^{2} \: \theta - cos^{2} \: \theta + 2 \: cos \: \theta } \\ \\$

$: \implies \tt\dfrac{2 (1 - \: cos \: \theta )- 2 \: sin \: \theta (1 - \: cos \: \theta)}{ 2 \: cos \: \theta - 2 \: cos^{2} \: \theta} \\ \\$

$: \implies \tt\dfrac{(2 + 2 \: sin \: \theta) \: \cancel{(1 - cos\: \theta)}}{2 \: cos \: \theta \: \cancel{(1 - cos \: \theta)}} \: = \: \dfrac{1 + sin \: \theta}{cos \: \theta} \\ \\$