Answer:
5 (8a + 1)
Step-by-step explanation:
Since they both can be factored by 5 you would divide both by 5 and get 8 and 1.
Answer:
Because the sectors are of equal size, each sector has the same probability of happening.
So for every number, you have a probability of 0.2 of it appearing.
Because you have three odd numbers, the probability to land on an odd number on each spin is 0.6. You can also say that the probability to not have an odd number is 0.4.
So what is the probability to have 0 odd number in two spins?
What is the probability to have 1 odd number in two spins? You can have one odd number on the first or one odd on the second spin, that is why we add the probabilities.
What is the probability to have 2 odd numbers in two spins?
To verify if we did a good job, we add all the probabilities. We should get 1.
.
So to slide your bars, you slide them up to the number I gave you for each case.
Hope this helps!
Answer:
236462700.81
Step-by-step explanation:
The nearest cent refers to the hundreds place, because 100 pennies (or cents) make 1 dollar. We look at the number to the right of the hundredths place and if it is less than 5 we round down, but if it is 5 or more we round up. Since 6 is more than five we round up, and are left with 236462700.81.
Answer: 0.1357
Step-by-step explanation:
Given : Monitors manufactured by TSI Electronics have life spans that have a normal distribution with a variance of 
and a mean life span of 
hours.
Here , 
Let x represents the life span of a monitor.
Then , the probability that the life span of the monitor will be more than 14,650 hours will be :-
![P(x>14650)=P(\dfrac{x-\mu}{\sigma}>\dfrac{14650-13000}{1500})\\\\=P(z>1.1)=1-P(z\leq1.1)\ \ [\because\ P(Z>z)=1-P(Z\leq z)]\\\\=1-0.8643339=0.1356661\approx0.1357](https://tex.z-dn.net/?f=P%28x%3E14650%29%3DP%28%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%3E%5Cdfrac%7B14650-13000%7D%7B1500%7D%29%5C%5C%5C%5C%3DP%28z%3E1.1%29%3D1-P%28z%5Cleq1.1%29%5C%20%5C%20%5B%5Cbecause%5C%20P%28Z%3Ez%29%3D1-P%28Z%5Cleq%20z%29%5D%5C%5C%5C%5C%3D1-0.8643339%3D0.1356661%5Capprox0.1357)
Hence, the probability that the life span of the monitor will be more than 14,650 hours = 0.1357
