Answer:
The specific heat capacity of the metal is 1.307 J/g °C
Explanation:
<u>Step 1:</u> Data given
mass of the metal = 312 grams
initial temperature of the metal ( before plunged in the water) = 277.845 °C
initial temperature water = 11.945 °C
Final temperature of water (and aslo the metal) = 99.062 °C
Specific heat capacity of wayer = 4.184 J/g °C
<u>Step 2:</u> Calculate the specifi heat capacity of the metal
Loss of Heat of the Metal = Gain of Heat by the Water
Qmetal = -Qwater
m(metal) * C(metal) * ΔT(metal) = - m(water) * C(water) * ΔT(water)
with mass of metal = 312 grams
with C(metal) = TO BE DETERMINED
with ΔT (metal) = 99.062 - 277.845 = -178.783 °C
with mass of water = 200 grams
with C(water) = 4.184 J/°C * g
with ΔT (water) = 99.062 - 11.945 = 87.117 °C
312 * C(metal) * -178.783 = - 200* 4.184 * 87.117
C(metal) = -72899.51 / 55780.296 = 1.307
The specific heat capacity of the metal is 1.307 J/g °C
