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2 years ago

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A saturated solution of potassium chlorate is dissolved in 100g of water. If the saturated solution is cooled from 90 degrees Ce

lsius to 60 degrees Celsius, how many grams would crystallize out?

1 answer:

dedylja [7]2 years ago

4 0

Mass would crystallize out : 24 g

<h3>Further explanation </h3>

Solubility is the maximum amount of a substance that can dissolve in some solvents. Factors that affect solubility

1. Temperature:
2. Surface area:
3. Solvent type:
4. Stirring process:

We can use solubility graph to solve this.

solubility KClO₃ at 90°C=52 g

solubilty KCl₃ at 60°C= 28 g

Mass would crystallize out = 52 - 28 =24 g

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Select the appropriate words to fill in the blanks. A solution in which no more solute can be dissolved in is referred to as ___

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Answer:

A solution in which no more solute can be dissolved in is referred to as SATURATED. In such a solution, the concentration of solute is called SOLUBILITY . When that concentration is reported in moles per liter, it is more specifically called MOLAR SOLUBILITY. A special equilibrium constant called the SOLUBILITY PRODUCT constant is calculated from the molar concentrations of the aqueous components of the dissolution equation.

Explanation:

The solubility of a solute in a solvent is the maximum amount of solute in moles that will be dissolved in 1dm3 of the solvent at a specified temperature. Once the maximum number or concentration has been reached, the solvent can no longer take in solutes and this point in the reaction, the solution is said to be saturated. That is the composition of the saturated solution is not affected by the presence of excess solute. An unsaturated solution has a lower concentration of solute and can dissolve more solutes if added until it becomes saturated.

Solubility when reported in moles per liter is called molar solubility of the solution and it gives a more accurate measurement of yh solubility of a solution. The solubility product constant is calculated from the molar concentrations of the aqueous components of the dissolution equation. This solubility product constant explains the balance between dissolved ions from the salt and undissolved salt in a dissolution equation.

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3 years ago

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What would be the composition and ph of an ideal buffer prepared from lactic acid (ch3chohco2h), where the hydrogen atom highlig

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Answer:

$P_H =2.86$

$c=1.4\times 10^{-4}$

Explanation:

first write the equilibrium equaion ,

$C_3H_6O_3$ ⇄ $C_3H_5O_3^{-} +H^{+}$

assuming degree of dissociation $\alpha$ =1/10;

and initial concentraion of $C_3H_6O_3$ =c;

At equlibrium ;

concentration of $C_3H_6O_3 = c-c\alpha$

$[C_3H_5O_3^{-} ]= c\alpha$

$[H^{+}] = c\alpha$

$K_a = \frac{c\alpha \times c\alpha}{c-c\alpha}$

$\alpha$ is very small so $1-\alpha$ can be neglected

and equation is;

$K_a = {c\alpha \times \alpha}$

$[H^{+}] = c\alpha$ = $\frac{K_a}{\alpha}$

$P_H =- log[H^{+} ]$

$P_H =-logK_a + log\alpha$

$K_a =1.38\times10^{-4}$

$\alpha = \frac{1}{10}$

$P_H= 3.86-1$

$P_H =2.86$

composiion ;

$c=\frac{1}{\alpha} \times [H^{+}]$

$[H^{+}] =antilog(-P_H)$

$[H^{+} ] =0.0014$

$c=0.0014\times \frac{1}{10}$

$c=1.4\times 10^{-4}$

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Na because its a metal. Metals are the best conductors. S and Ne are nonmetals. and Ge is a metalloid. (Metalloids are semi conductors)

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Explanation:

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Answer:

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