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2 years ago

Can you guys help this is a test plz help

Mathematics

2 answers:

Oksanka [162]2 years ago

7 0

Answer:

141.6

Step-by-step explanation:

DENIUS [597]2 years ago

6 0

141.6

Step-by-step explanation:

&4&74:+85468967

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0.75(3.55a - 6b) simplified please

GREYUIT [131]

Answer:

Step-by-step explanation:

2.66a-6b

3 0

3 years ago

Solve 4e^2x-3=12 please help

Anestetic [448]

$4*e^{2x} -3 = 12$

Step 1:

Here we have -3 in subtraction on the left side, so when we take it to the right we apply opposite operation of subtraction that is addition.

$4*e^{2x} = 12+3$

$4*e^{2x} = 15$

Step 2:

Next we have 4 in multiplication on left side, so dividing right side by 4,

$e^{2x} = 15/4$

$e^{2x} = 3.75$

Step 3:

taking log on both sides

$ln ( e^{2x}) = ln(3.75)$

${2x} =ln 3.75$

Step 4:

Dividing right side by 2,

x= ln (3.75) /2 = 0.66088

Answer : x = 0.66088..

5 0

3 years ago

Read 2 more answers

g A manufacturer is making cylindrical cans that hold 300 cm3. The dimensions of the can are not mandated, so to save manufactur

sdas [7]

Answer:

The dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.

Step-by-step explanation:

A cylindrical can holds 300 cubic centimeters, and we want to find the dimensions that minimize the cost for materials: that is, the dimensions that minimize the surface area.

Recall that the volume for a cylinder is given by:

$\displaystyle V = \pi r^2h$

Substitute:

$\displaystyle (300) = \pi r^2 h$

Solve for <em>h: </em>

$\displaystyle \frac{300}{\pi r^2} = h$

Recall that the surface area of a cylinder is given by:

$\displaystyle A = 2\pi r^2 + 2\pi rh$

We want to minimize this equation. To do so, we can find its critical points, since extrema (minima and maxima) occur at critical points.

First, substitute for <em>h</em>.

$\displaystyle \begin{aligned} A &= 2\pi r^2 + 2\pi r\left(\frac{300}{\pi r^2}\right) \\ \\ &=2\pi r^2 + \frac{600}{ r} \end{aligned}$

Find its derivative:

$\displaystyle A' = 4\pi r - \frac{600}{r^2}$

Solve for its zero(s):

$\displaystyle \begin{aligned} (0) &= 4\pi r - \frac{600}{r^2} \\ \\ 4\pi r - \frac{600}{r^2} &= 0 \\ \\ 4\pi r^3 - 600 &= 0 \\ \\ \pi r^3 &= 150 \\ \\ r &= \sqrt[3]{\frac{150}{\pi}} \approx 3.628\text{ cm}\end{aligned}$

Hence, the radius that minimizes the surface area will be about 3.628 centimeters.

Then the height will be:

$\displaystyle \begin{aligned} h&= \frac{300}{\pi\left( \sqrt[3]{\dfrac{150}{\pi}}\right)^2} \\ \\ &= \frac{60}{\pi \sqrt[3]{\dfrac{180}{\pi^2}}}\approx 7.25 6\text{ cm} \end{aligned}$

In conclusion, the dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.

7 0

2 years ago

HELPPPP PLEASEEEEE

Alecsey [184]

I’m not rly sure what it means by flipping the card …. I’m assuming there’s more to this question but if it’s what I think it is the only way this equation will be true is by switching the + Symbol to - (subtraction) which would be 1-2= 3-4 since it would 1=1 making the equation true

7 0

2 years ago

NEED HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

e-lub [12.9K]

The formula for circumference = 2*Pi*r
R= radius. Radius is half of the diameter, and d= 20. This means that radius = 10. Now we have a full formula to work with.2*Pi*10.
Substitute 3.14 for pi.
3.14 * 10 = 31.4.
31.4*2 = 62.8.
62.8 rounded equals 63.
C = 63.

5 0

2 years ago