All categories

3 years ago

3 of 4

Mathematics

1 answer:

vfiekz [6]3 years ago

5 0

Answer:

45% of the students prefer biology

Step-by-step explanation:

Let's read and write all the data from the question.

100 students are interviewed to see which of biology, chemistry and physics they prefer.

Therefore, we have three categories to classify the students :

A student that prefers biology

A student that prefers chemistry

And a student that prefers physics

52 of the students are girls. Therefore,

students are boys.

29 of the girls like biology best. In order to answer the question, we will only need the amount of boys that prefer biology and sum them to the amount of girls that like biology best.

24 of the boys prefer physics. Therefore,

is the sum of the boys that prefer chemistry and biology.

If 24 is the sum of the boys that prefer chemistry and biology ⇒

are boys that prefer biology.

If we sum is the number of students that prefer biology.

If we want to calculate the percentage we need to divide the amount of students that prefer biology by the total of students interviewed and then multiply that number by 100 :

45 % of the students prefer biology.

You might be interested in

Plz help for points plzzz

White raven [17]

Answer: 5.3

Step-by-step explanation: Do 9.8 (Friend swim depth) - 4.5 (dolphin jump height) to get your answer.

4 0

3 years ago

Read 2 more answers

Find all solutions of the equation: 2cos^2x-cosx=1

Art [367]

If you're using the app, try seeing this answer through your browser: brainly.com/question/3166243

——————————

Solve the trigonometric equation:

$\mathsf{2\,cos^2\,x-cos\,x=1}\\\\ \mathsf{2\,cos^2\,x-cos\,x-1=0}$

Make a substitution:

$\mathsf{cos\,x=t\qquad (-1\le t\le 1)}$

and the equation becomes

$\mathsf{2t^2-t-1=0}$

Rewrite conveniently – t as + t – 2t, and then factor the left-hand side by grouping:

$\mathsf{2t^2+t-2t-1=0}\\\\ \mathsf{t\cdot (2t+1)-1\cdot (2t+1)=0}$

Factor out 2t + 1:

$\mathsf{(2t+1)\cdot (t-1)=0}\\\\ \begin{array}{rcl} \mathsf{2t+1=0}&~\textsf{ or }~&\mathsf{t-1=0}\\\\ \mathsf{2t=1}&~\textsf{ or }~&\mathsf{t=1}\\\\ \mathsf{t=\dfrac{\,1\,}{2}}&~\textsf{ or }~&\mathsf{t=1} \end{array}$

Substitute back for t = cos x:

$\begin{array}{rcl}\mathsf{cos\,x=\dfrac{\,1\,}{2}}&~\textsf{ or }~&\mathsf{cos\,x=1}\\\\ \mathsf{cos\,x=cos\,60^\circ}&~\textsf{ or }~&\mathsf{cos\,x=cos\,0} \end{array}$

Therefore,

$\begin{array}{rcl} \mathsf{x=\pm\,60^\circ+k\cdot 360^\circ}&~\textsf{ or }~&\mathsf{cos\,x=0+k\cdot 360^\circ} \end{array}$

where k is an integer.

Solution set:

$\mathsf{S=\left\{x\in\mathbb{R}:~~x=-\,60^\circ+k\cdot 360^\circ~~or~~x=60^\circ+k\cdot 360^\circ~~or~~x=k\cdot 360^\circ,~~k\in\mathbb{Z}\right\}}$

I hope this helps. =)

3 0

3 years ago

Area of a regular decagon with side length of 8in

Scrat [10]

Answer:

492.43in²

Step-by-step explanation:

I might be wrong.

4 0

3 years ago

A newspaper invited readers to call a telephone number and record their comments. The next day they reported that readers overwh

maks197457 [2]

Answer: Self selected sample

Step-by-step explanation:

They people chose themselves

4 0

3 years ago

Which one is the correct answer?

Molodets [167]

The answer selected is the correct answer because all of the other ones are equivalent to each other.

5 0

3 years ago