Which of these equations are in slope-intercept form?

Equations with parentheses may require the use of the distributive property to be solve

Mamont248 [21]

If this is a T/F question, then your answer is True .-.

8 0

3 years ago

The volumes of two similar figures are given. The surface area of the larger figure is given. Find the surface area of the small

frez [133]

Answer:

surface area of the smaller figure ≈ 1474.64 m²

Step-by-step explanation:

The figures are similar base on the question . The surface area and the volume of the larger figure is given while only the figure of the smaller figure is given.

To find the surface area of the smaller figure we simply use the ratios. That is the scale factors.

Therefore, they are similar figure the scale factor can be represented as a:b.

The scale factor for volume is cubed.

volume of larger figure/volume of the small figure = a³/b³

4536/2625 = a³/b³

a/b = 16.5535451/13.7946209

Note that for two similar solid with scale factor a:b the surface area ratio is a²: b² (the scale factor is square)

16.55²/13.79² = 2124/x

273.9025/190.1641 = 2124/x

cross multiply

273.9025x = 403908.54840

x = 403908.54840/273.9025

x = 1474.6435261

x ≈ 1474.64 m²

4 0

4 years ago

Which choice is equivalent to the expression below?

Andre45 [30]

Answer:

C. $4\sqrt{7} -4x\sqrt{7}$ is correct

Steps:

$4\sqrt{7} -3\sqrt{7}x-x\sqrt{7} \\\\4\sqrt{7} -3\sqrt{7} x-\sqrt{7} x\\\\4\sqrt{7} +(-3\sqrt{7} x-\sqrt{7} x)\\\\4\sqrt{7} -4\sqrt{7} x$

7 0

3 years ago

Read 2 more answers

What is the radius of 81π square inches

MrRa [10]

It is 9 inches because the formula for the area of a circle is πr2 where the r represents the radius of the circle

The pi can be canceled out =

πr2 and 81 π leaving with

R2 and 81

The r2 represents a square number. So square root 81 and you would result in 9 as your answer

3 0

4 years ago

A sanitation department is interested in estimating the mean amount of garbage per bin for all bins in the city. In a random sam

soldi70 [24.7K]

Answer:

a) $52.8-2.02\frac{3.9}{\sqrt{40}}=51.554$

b) $52.8+2.02\frac{3.9}{\sqrt{40}}=54.046$

c) $52.8-2.71\frac{3.9}{\sqrt{40}}=51.129$

d) $52.8+2.71\frac{3.9}{\sqrt{40}}=54.471$

e) Yes, depends of the confidence level.

At 95 % of confidence the value 54.1985 pounds is not included on the interval. At 5% of significance the statement is FALSE.

At 99 % of confidence the value 54.1985 pounds is included on the interval. So at 1% of significance the statement is TRUE.

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X =52.8$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s=3.9 represent the sample standard deviation

n=40 represent the sample size

a) What is the lower limit of the 95% interval? Give your answer to three decimal places

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the mean and the sample deviation we can use the following formulas:

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=40-1=39$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,39)".And we see that $t_{\alpha/2}=2.02$

Now we have everything in order to replace into formula (1):

$52.8-2.02\frac{3.9}{\sqrt{40}}=51.554$

b) What is the upper limit of the 95% interval? Give your answer to three decimal places

$52.8+2.02\frac{3.9}{\sqrt{40}}=54.046$

So on this case the 95% confidence interval would be given by (51.554;54.046)

c) What is the lower limit of the 99% interval? Give your answer to three decimal places

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,39)".And we see that $t_{\alpha/2}=2.71$

Now we have everything in order to replace into formula (1):

$52.8-2.71\frac{3.9}{\sqrt{40}}=51.129$

d) What is the upper limit of the 99% interval? Give your answer to three decimal places

$52.8+2.71\frac{3.9}{\sqrt{40}}=54.471$

So on this case the 99% confidence interval would be given by (51.129;54.471)

e) Consider the claim that the mean amount of garbage per bin is 54.1985 pounds. Is the following statement true or false? The decision about the claim would depend on whether we use a 95% or 99% confidence interval: True/False

Yes, depends of the confidence level.

At 95 % of confidence the value 54.1985 pounds is not included on the interval. At 5% of significance the statement is FALSE.

At 99 % of confidence the value 54.1985 pounds is included on the interval. So at 1% of significance the statement is TRUE.

3 0

4 years ago