A number is of another number. The difference of the

Steve opens a bank account with a simple annual interest rate of 5%. After four years, how much interest will Steve earn on an i

Marysya12 [62]

Steve will earn $160 interest after four years ⇒ 1st answer

Step-by-step explanation:

The formula of the simple interest is I = Prt, where

P is the initial deposit
r is the annual rate in decimal
t is the time of investment

∵ Steve opens a bank account with a simple annual interest rate of 5%

∴ r = 5% = 5 ÷ 100 = 0.05

∵ His initial deposit is $800

∵ He will put the money for four years

∴ t = 4

- Substitute all these values in the formula above

∵ I = 800(0.05)(4)

∴ I = 160

Steve will earn $160 interest after four years

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You can learn more about the interest in brainly.com/question/13018049

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7 0

3 years ago

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What is the value of w? A.) 7 B.) 3.5 C.) 7 square root of 3 D.) 14

sammy [17]

D. 14

LL = 1/2 * Hsqrt3
7sqrt3 = 1/2 * ysqrt3
24.25 = ysqrt3
24.25/sqrt3 = y
y = 14

4 0

3 years ago

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What is the true solution to the equation below? ln e^lnx^2=2 ln 8?

arlik [135]

$x\ \textgreater \ 0\\\\
\ln e^{\ln x}+\ln e^{\ln x^2}=2\ln 8\\
\ln x+\ln x^2=\ln 8^2\\
\ln (x\cdot x^2)=\ln 64\\
\ln x^3=\ln 64\\
x^3=64\\
x=4\Rightarrow \text {B}
$

6 0

3 years ago

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Explain why 1/2 is not equivalent to 2/5.

juin [17]

Find ing the common denominator would make it 10.
for 1/2 to get to 10 you have to multiply by 5
1/2x5= 5/10
then you have to convert 2/5 to get the denominator to be 10
so you multiply 2/5 by 2
2/5x2= 4/10
5/10 is greater than 4/10

7 0

3 years ago

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A study by the National Athletic Trainers Association surveyed random samples of 1679 high school freshmen and 1366 high school

nekit [7.7K]

Answer:

We conclude that there is no significant difference in the proportion of all Illinois high school freshmen and seniors who have used anabolic steroids.

Step-by-step explanation:

We are given that a study by the National Athletic Trainers Association surveyed random samples of 1679 high school freshmen and 1366 high school seniors in Illinois.

Results showed that 34 of the freshmen and 24 of the seniors had used anabolic steroids.

Let $p_1$ = proportion of Illinois high school freshmen who have used anabolic steroids.

$p_2$ = proportion of Illinois high school seniors who have used anabolic steroids.

SO, Null Hypothesis, $H_0$ : $p_1=p_2$ {means that there is no significant difference in the proportion of all Illinois high school freshmen and seniors who have used anabolic steroids}

Alternate Hypothesis, $H_A$ : $p_1\neq p_2$ {means that there is a significant difference in the proportion of all Illinois high school freshmen and seniors who have used anabolic steroids}

The test statistics that would be used here Two-sample z test for proportions;

T.S. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of high school freshmen who have used anabolic steroids = $\frac{34}{1679}$ = 0.0203

$\hat p_2$ = sample proportion of high school seniors who have used anabolic steroids = $\frac{24}{1366}$ = 0.0176

$n_1$ = sample of high school freshmen = 1679

$n_2$ = sample of high school seniors = 1366

So, the test statistics = $\frac{(0.0203-0.0176)-(0)}{\sqrt{\frac{0.0203(1-0.0203)}{1679}+\frac{0.0176(1-0.0176)}{1366} } }$

= 0.545

The value of z test statistics is 0.545.

Since, in the question we are not given with the level of significance so we assume it to be 5%. Now, at 5% significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

Since our test statistic lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that there is no significant difference in the proportion of all Illinois high school freshmen and seniors who have used anabolic steroids.

3 0

3 years ago