Answer:
The probability that at least 1 defective card is in the sample is 
Step-by-step explanation:
Here
N = 140
and n = 20
We will use the below given formula
P(at least 1 defective) = 1 - P( 0 defectives)
P( 0 defectives) =

Answer:
the sample standard deviation
Step-by-step explanation:
The statistic that would enable Dan to estimate the probability that any single class will last somewhere between 47 and 53 minutes is the sample standard deviation. If we have the mean and the standard deviation and we know that the lenghts of the classes form a normal curve, we can compute probabilities either with the empirical rule or using a table of probabilities from a book. The normal distribution is completely determined with the mean and the standard deviation.
For 27 since all they did was add a zero on the end of the first number (9,554), you just add that zero to the end of you quotient to make 95,540 / 562 = 170
For 28 the answer is 110.59 (rounded to nearest hundredth) because you take the distance between the moon and earth and divide it by the width of the moon 384,400 / 3,476 = 110.58688
Hope this helps!