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3 years ago

there are 96 boys and 120 girls in grade 9. write down the ratio of the number of boys to the number of girls in the class.

Mathematics

1 answer:

Alenkasestr [34]3 years ago

5 0

Step-by-step explanation:

96/120=8/12

=2/3

ratio of boys to girls in the class

=2:3

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There were 27 bales of hay in the barn. Grant stacked some more bales in the barn.Now there are 76 bales. Let b be the number of

lutik1710 [3]

Answer:

b=49

Step-by-step explanation:

27+b=76

76-27= 49

b=49

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3 years ago

Please Help! Thanks to whoever can answer this!

Illusion [34]

Here, we are missing the slope and the y intercept.

Lets look for the y intercept first.

Where does it cross the y axis? At 3!!

3 is the y intercept.

Now, find the slope by using the slope formula.

$m = \frac{y2 - y1}{x2 - x1}$
(0,3) and (2,1)

m = 1-3/2-0 = -2/2 = -2/2 = -1
m = -1

Okay, so we found our slope, now just write the equation.

Answer: y = -1x + 3

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3 years ago

What is the Domain and Range of the function f(x)<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx-7%7D%20%2B9" id="TexFormula1" tit

omeli [17]

For the given function, the domain is D : { x ≥ 7} and the range is R: { y ≥ 9}

<h3>How to get the domain and range?</h3>

Here we have a square root, remember that the argument of the square root must be equal or larger than zero, so the domain is such that:

x - 7 ≥ 0.

Solving for x we get:

x ≥ 0 + 7

Then the domain is:

x ≥ 7

To get the range, we evaluate in the minimum of the domain:

f(7) = √(7 - 7) + 9 = 9

Then the range is the set of all values larger than 9, because the function is increasing.

So the range is R: y ≥ 9.

If you want to learn more about domain and range:

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2 years ago

Find the value of x

kodGreya [7K]

Answer:

Last Option

Step-by-step explanation:

We have a triangle and we know its three sides.

We want to find one of your anguos. Then we use the cosine theorem.

$c ^ 2 = a ^ 2 + b ^ 2 -2abcosx$

Where

$c = 14\\a = 11\\b = 19$

Now we solve for x from the equation

$c ^ 2 = a ^ 2 + b ^ 2 -2abcosx\\\\\\14^2 = 11^2 + 19^2 -2(11)(19)cosx\\\\14^2 -11^2 -19^2 = 2(11)(19)cosx\\\\-286=2(11)(19)cosx\\\\cosx = \frac{-286}{2(11)(19)}\\\\x = arcos(\frac{-286}{2(11)(19)})\\\\x = 46.8\°$

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3 years ago

Read 2 more answers

Suppose you can somehow choose two people at random who took the SAT in 2014. A reminder that scores were Normally distributed w

Sindrei [870]

Answer:

22.29% probability that both of them scored above a 1520

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 1497, \sigma = 322$

The first step to solve the question is find the probability that a student has of scoring above 1520, which is 1 subtracted by the pvalue of Z when X = 1520.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{1520 - 1497}{322}$

$Z = 0.07$

$Z = 0.07$ has a pvalue of 0.5279

1 - 0.5279 = 0.4721

Each students has a 0.4721 probability of scoring above 1520.

What is the probability that both of them scored above a 1520?

Each students has a 0.4721 probability of scoring above 1520. So

$P = 0.4721*0.4721 = 0.2229$

22.29% probability that both of them scored above a 1520

8 0

3 years ago

there are 96 boys and 120 girls in grade 9. write down the ratio of the number of boys to the number of girls in the class.​

there are 96 boys and 120 girls in grade 9. write down the ratio of the number of boys to the number of girls in the class.