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soldi70 [24.7K]
3 years ago
9

Math work please help wioth my math

Mathematics
2 answers:
Juli2301 [7.4K]3 years ago
7 0

Answer:

Figure A is scalene and probably obtuse.

Figure B is scalene and right.

Figure C is equilateral and acute.

Figure D is isosceles and right.

Figure E is isosceles and acute.

I am so sorry if I did a few wrong, I'm in Middle-School so I don't know much. I hope I get everything correct!

ozzi3 years ago
3 0

Answer: Figure A is scalene and probably obtuse.

Figure B is scalene and right.

Figure C is equilateral and acute.

Figure D is isosceles and right.

Figure E is isosceles and acute.

Step-by-step explanation:

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Which factor does the width of the peak of a normal curve depend on?
trasher [3.6K]
The answer would be standard deviation.
7 0
3 years ago
Read 2 more answers
2. How many square yards of carpet will be needed for a 21 ft by 15 ft room?
ipn [44]

Answer:

The answer to your question is: 35 yd²

Step-by-step explanation:

To solve this problem, just find the data, the formula, substitute the values in the formula and find the result.

Data

Square yards = ?

Length = 21 ft

Width = 15 ft

Formula

Area of a rectangle = length x width

Substitution

Area of a rectangle = 21 ft x 15 ft

Area of a rectangle = 315 ft²

Area of a rectangle = square yards of carpet

Finally, convert ft² to yd²

315 ft² = 35 yd²

Result

Square yards of carpet = 35 yt²

7 0
3 years ago
Solve the inequality: -3x - 5 _&gt; 7
amid [387]

Answer:

x< -4

Step-by-step explanation:

4 0
3 years ago
Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in
Law Incorporation [45]

Answer:

(a) 900

(b) [567.35 , 1689.72]

(c) [23.82 , 41.11]

Step-by-step explanation:

We are given that a sample of 20 days of operation shows a sample mean of 290 rooms occupied per  day and a sample standard deviation of 30 rooms i.e.;

Sample mean, xbar = 290      Sample standard deviation, s = 30  and  Sample size, n = 20

(a) Point estimate of the population variance is equal to sample variance, which is the square of Sample standard deviation ;

                         \sigma^{2}  =  s^{2} = 30^{2}

                          \sigma^{2}  = 900

(b) 90% confidence interval estimate of the population variance is given by the pivotal quantity of  \frac{(n-1)s^{2} }{\sigma^{2} } ~ \chi^{2} __n_-_1

P(10.12 < \chi^{2}__1_9 < 30.14) = 0.90 {At 10% significance level chi square has critical

                                           values of 10.12 and 30.14 at 19 degree of freedom}        

P(10.12 < \frac{(n-1)s^{2} }{\sigma^{2} } < 30.14) = 0.90

P(\frac{10.12}{(n-1)s^{2} } < \frac{1 }{\sigma^{2} } < \frac{30.14}{(n-1)s^{2} } ) = 0.90

P(\frac{(n-1)s^{2} }{30.14} < \sigma^{2} < \frac{(n-1)s^{2} }{10.12} ) = 0.90

90% confidence interval for \sigma^{2} = [\frac{19s^{2} }{30.14} , \frac{19s^{2} }{10.12}]

                                                   = [\frac{19*900 }{30.14} , \frac{19*900 }{10.12}]

                                                   = [567.35 , 1689.72]

Therefore, 90% confidence interval estimate of the population variance is [567.35 , 1689.72] .

(c) 90% confidence interval estimate of the population standard deviation is given by ;

       P(\sqrt{\frac{(n-1)s^{2} }{30.14}} < \sigma < \sqrt{\frac{(n-1)s^{2} }{10.12}} ) = 0.90

90% confidence interval for \sigma = [\sqrt{\frac{19s^{2} }{30.14}}   , \sqrt{\frac{19s^{2} }{10.12}}  ]

                                                 = [23.82 , 41.11]

Therefore, 90% confidence interval estimate of the population standard deviation is [23.82 , 41.11] .

7 0
3 years ago
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